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3 years ago

How many moles are in 2.5g of n2

Chemistry

2 answers:

exis [7]3 years ago

7 0

n= m/M = 2.5/14 = 5/28 mol

ok done. thank to me :>

Thepotemich [5.8K]3 years ago

6 0

Answer:

0.089

Explanation:

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What molecular formulas has the same empirical formula

wlad13 [49]

Answer:, formaldehyde

Explanation:

each molecule of which consists of one carbon atom, two hydrogen atoms, and one oxygen atom, has the molecular formula CH2O, which is identical to the empirical formula of glucose.

If this helps.

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3 years ago

Deploying an airbag in an automobile is a complex process. Identify at least three steps in the process. Refer to your research

gavmur [86]

Answer:

1) The car must have an accelerometer and airbag circut.

2) Chemical explosive of enough sodium azide to fill the bag when ignited

3) Airbag can be covered in talcum powder to help it unwrap smoothly.

Explanation:

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3 years ago

g (2pts) A 10x transfer buffer solution is 250mM Tris and 1.92M glycine. Buffers are always used at 1x concentration in the lab

uranmaximum [27]

Answer:

The explanation according to the given question is summarized below.

Explanation:

Given:

Tris,

= 250 mM

Glycine,

= 1.92 M

According to the solution,

For the dilution pf 10X to 1X buffer, we get

= $1 \ ml \ of \ 10X \ buffer +9 \ ml \ of \ distilled \ water$

= $10$

i.e.,

⇒ $10X \ to \ 1X=1:10 \ dilution$

Now,

⇒ $10X (250 \ mM\ Tris \ HCl, 1.92M\ Glycine, and\ 1 \ percent (\frac{w}{v} ) SDS) ---->1X(25 \ mM \ Tris \ HCl,0.193 M\ Glycine, and \ 0.1 \ percent(\frac{w}{v} )SDS)$

8 0

3 years ago

How much energy is produced in the creation of 5 grams of "O by the process: (10 pts.) 14N + α. 'H + 170 ("N-14.00307 gmole, α-4

LenKa [72]

Answer : The energy produced is $3.410\times 10^{10}J$

Explanation :

First we have to calculate the moles of $^{17}O$ .

$\text{Moles of }^{17}O=\frac{\text{Mass of }^{17}O}{\text{Molar mass of }^{17}O}=\frac{5g}{16.99913g/mole}=0.294133moles$

Now we have to calculate the mass defect.

The balanced reaction is,

$^{14}N+\alpha \rightarrow ^1H+^{17}O$

Mass defect = Sum of mass of product - sum of mass of reactants

$\Delta m=[(n_{^1H}\times M_{^1H})+(n_{^{17}O}\times M_{^{17}O})]-[(n_{^{14}N}\times M_{^{14}N})+(n_{\alpha}\times M_{\alpha})]$

where,

n = number of moles = 0.294133 moles

M = molar mass

Now put all the given values in the above, we get:

$\Delta m=[(n_{^1H}\times M_{^1H})+(n_{^{17}O}\times M_{^{17}O})]-[(n_{^{14}N}\times M_{^{14}N})+(n_{\alpha}\times M_{\alpha})]$

$\Delta m=[(0.294133mole\times 1.00783g/mole)+(0.294133mole\times 16.99913g/mole)]-[(0.294133mole\times 14.00307g/mole)+(0.294133mole\times 4.0026g/mole)]$

$\Delta m=0.00037943157g=3.7943157\times 10^{-7}kg$

Now we have to calculate the energy produced.

$Energy=\Delta m\times (c)^2$

$Energy=(3.7943157\times 10^{-7}kg)\times (299792458m/s)^2$

$Energy=3.410\times 10^{10}J$

Therefore, the energy produced is $3.410\times 10^{10}J$

3 0

4 years ago

A substance can absorb or release heat energy by the process of

Lina20 [59]

<span>A substance can absorb or release heat energy by the process of radiation, convection, or conduction. Radiation refers to the transfer of energy through emission of electromagnetic waves or the movement of particles. An example of radiation is the Sun’s rays. This type of heat transfer does not require direct contact between objects. Convection, on the other hand, involves the hotter fluid rising while the colder fluid sinks. Convection occurs when you boil water in a pan. Lastly, conduction is a heat transfer that occurs as a result of temperature difference between two objects in contact. Heat is transferred from the hotter region to the colder region. Conduction occurs when ice melts in your hands. </span>

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3 years ago