Question

If the molar concentration of sodium sulfate (Na2SO4) is 0.10 M, what is the concentration of sodium ion

Answer 1

Na2SO4 --> 2Na+ + SO4 2-

0.1 x 2 = 0.2 M

Answer 2

Answer : The concentration of sodium ions in a $Na_2SO_4$ solution is 0.20 M

Explanation :

The dissociation reaction of $Na_2SO_4$ in solution will be:

$Na_2SO_4\rightarrow 2Na^++SO_4^{2-}$

From the reaction we conclude that, 1 mole of $Na_2SO_4$ dissociate in solution to give 2 moles of $Na^+$ ion (sodium ion) and 1 mole of $SO_4^{2-}$ ion (sulfate ion).

As per question,

0.10 M of $Na_2SO_4$ dissociate in solution to give $2\times 0.10M=0.20M$ of $Na^+$ ion (sodium ion) and 0.10 M of $SO_4^{2-}$ ion (sulfate ion).

Hence, the concentration of sodium ions in a $Na_2SO_4$ solution is 0.20 M