Answer:
Explanation:
The relation between time period of moon in the orbit around a planet can be given by the following relation .
T² = 4 π² R³ / GM
G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .
Substituting the values in the equation
(.3189 x 24 x 60 x 60 s)² = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)
759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )
M = .06424 x 10²⁵
= 6.4 x 10²³ kg .
Given:
Height of tank = 8 ft
and we need to pump fuel weighing 52 lb/ 
to a height of 13 ft above the tank top
Solution:
Total height = 8+13 =21 ft
pumping dist = 21 - y
Area of cross-section = 
= 
=16
Now,
Work done required = 
= 
= 832
![[ 21y ]_{0}^{8} - [\frac{y^{2}}{2}]_{0}^{8}\\](https://tex.z-dn.net/?f=%5B%2021y%20%5D_%7B0%7D%5E%7B8%7D%20-%20%5B%5Cfrac%7By%5E%7B2%7D%7D%7B2%7D%5D_%7B0%7D%5E%7B8%7D%5C%5C)
)
= 113152 = 355477 ft-lb
Therefore work required to pump the fuel is 355477 ft-lb
Let's apply an equation of equilibrium to the situation: The sum of the moments about the left end of the board must equal 0.
We have three moments to add. Positive force values indicate upward direction and negative values indicate downward direction. All distances given below are measured to the right side of the left end of the board:
- The weight of the board, -125N, located at 2m (center of the board due to its uniform density)
- The tension in the right chain, +250N, located at 4m
- The weight of the person, -500N, located at a distance "x"
The sum of the moments must equal 0 and is given by:
ΣFx = 0
F is the magnitude of force, x = distance from the left end of the board
Plug in all of the force and distance values and solve for x:
ΣFx = 250(4) - 125(2) - 500x = 0
500x = 750
x = 1.5m
D because choppy water is already a little bit of wave action and then the wind adds a lot of speed to the waves and height to the waves to meek the best waves. Hope this helped.
Answer:
dynamo generator could be the right ans
