A person with mass 65 kg, standing still, throws an object at 4 m/s. If the
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- initial velocity=u=24m/s
- Acceleration=a=4m/s^2
- Distance=s=96m
- Final velocity=v
Using 3rd equation of kinematics
The time taken for the two balls to hit each other is 8 s.
The given parameters:
- <em>Acceleration of the rocket, a = 2 m/s²</em>
- <em>Length of the chamber, s = 4 m</em>
- <em>Speed of the first ball, = V1 = 0.3 m/s</em>
- <em>Speed of the second ball, V2 = 0.2 m/s</em>
The time taken for the two balls to hit each other is calculated by applying relative velocity formula as shown below;
Thus, the time taken for the two balls to hit each other is 8 s.
Learn more about relative velocity here: brainly.com/question/17228388