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3 years ago

7

An alternating current consists of charges that: a.) turn on and off repeatedly. b.) move back and forth in a circuit. c.) flow

in one direction only. d.) flow in one direction in some devices and change direction in others.

2 answers:

GrogVix [38]3 years ago

7 0

B. Move back and forth in a circuit.

Sindrei [870]3 years ago

6 0

move back and forth in a circuit.

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jenyasd209 [6]

The new absloute temperature should be 4t.

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2 years ago

What do the arrows at point three indicate

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3 years ago

Which phrases describe all the outer planets’ motion? Select two options.

AysviL [449]

Answer:

Fast rotation

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3 years ago

Read 2 more answers

What is the ideal mechanical advantage of a lift that allows you raise a 90.0-kg refrigerator with 80.0 N of force?

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2 years ago

A satellite of mass M = 270kg is in circular orbit around the Earth at an altitude equal to the earth's mean radius (6370 km). A

zubka84 [21]

To solve this problem we will apply the concepts related to Orbital Speed as a function of the universal gravitational constant, the mass of the planet and the orbital distance of the satellite. From finding the velocity it will be possible to calculate the period of the body and finally the gravitational force acting on the satellite.

PART A)

$V_{orbital} = \sqrt{\frac{GM_E}{R}}$

Here,

M = Mass of Earth

R = Distance from center to the satellite

Replacing with our values we have,

$V_{orbital} = \sqrt{\frac{(6.67*10^{-11})(5.972*10^{24})}{(6370*10^3)+(6370*10^3)}}$

$V_{orbital} = 5591.62m/s$

$V_{orbital} = 5.591*10^3m/s$

PART B) The period of satellite is given as,

$T = 2\pi \sqrt{\frac{r^3}{Gm_E}}$

$T = \frac{2\pi r}{V_{orbital}}$

$T = \frac{2\pi (2*6370*10^3)}{5.591*10^3}$

$T = 238.61min$

PART C) The gravitational force on the satellite is given by,

$F = ma$

$F = \frac{1}{4} mg$

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3 years ago