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3 years ago

Kuiper Belt objects are composed of which substances? Select all that apply.

Physics

1 answer:

levacccp [35]3 years ago

8 0

IM sure there is C, D, and E in kuiper belts, but not really sure of silicon and iron

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Simplifying fractions<br>30 over 54

Veronika [31]

Answer:

5/9

Explanation:

First, find a common factor for 30 and 54.

30 and 54 can both be divided by 2.

30 divided by 2 = 15

54 divided by 2 = 27

So, your new fraction is 15/27.

However, don't stop there.

15 and 27 can both be divided by 3 as well.

15 divided by 3 = 5

27 divided by 3 = 9

So, your final answer is 5/9.

I hope this helps! :)

4 0

3 years ago

Read 2 more answers

Can someone please help me? Anyone? PLEASE:(

tatuchka [14]

Answer:

There's no question-

8 0

3 years ago

A single loop of nickel wire, lying flat in a plane, has an area of 7.40 cm^2 and a resistance of 2.40 Ω. A uniform magnetic fie

ale4655 [162]

Explanation:

It is given that,

Area of nickel wire, $A=7.4\ cm^2=7.4\times 10^{-4}\ m^2$

Resistance of the wire, R = 2.4 ohms

Initial value of magnetic field, $B_1=0.5\ T$

Final magnetic field, $B_2=3\ T$

Time, t = 1.12 s

Let I is the induced current in the loop of wire over this time. Te emf induced in the wire is given by Faraday's law as :

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{d(BA)}{dt}$

$\epsilon=-A\dfrac{d(B)}{dt}$

$\epsilon=-A\dfrac{B_2-B_1}{t}$

$\epsilon=-7.4\times 10^{-4}\times \dfrac{3-0.5}{1.12}$

$\epsilon=1.65\times 10^{-3}\ V$

Induced current in the loop of wire is given by :

$I=\dfrac{\epsilon}{R}$

$I=\dfrac{1.65\times 10^{-3}}{2.4}$

$I=6.87\times 10^{-4}\ A$

So, the induced current in the loop of wire over this time is $6.87\times 10^{-4}\ A$ . Hence, this is the required solution.

7 0

3 years ago

A 2.55 kg block starts from rest on a rough inclined plane that makes an angle of 60 degree with the horizontal. the coefficient

lorasvet [3.4K]

Answer:

Change in mechanical energy = work done by friction

so it is equal to

$W = -8.16 J$

Explanation:

As we know that change in mechanical energy must be equal to the work done by non conservative forces only

So here when block moves down the inclined plane then the work done by friction force is given as

$W = F.d$

here we have

$F = \mu F_n$

here we know that

$F_n = mg cos\theta$

so we have

$F_n = 2.55(9.81)(cos60)$

$F_n = 12.5 N$

Now the friction force on the block is given as

$F_f = \mu F_n$

$F_f = 0.25 \times 12.5$

$F_f = 3.13 N$

now work done by the friction is given as

$W = -(3.13)(2.61)$

$W = -8.16 J$

7 0

3 years ago

A soap bubble usually pops because some part of it becomes too thin due to evaporation or drainage of fluid. The change in thick

Lapatulllka [165]

Answer:

To understand why the change in thickness also changes the color of light the bubble reflects, we definitely know that

mλ = dsinθ

when d sin θ = mλ, we expect constructive interference

d = distance between the slits

θ = the angle relative to the incident direction

m = order of the interference

Hence, a change in the thickness will also cause a change in the wavelength, and as wavelength changes, various colors are generated.

The light's path difference is therefore generated as a result of the thickness variation of the soap bubble.

Explanation:

To understand why the change in thickness also changes the color of light the bubble reflects, we definitely know that

mλ = dsinθ

when d sin θ = mλ, we expect constructive interference

d = distance between the slits

θ = the angle relative to the incident direction

m = order of the interference

Hence, a change in the thickness will also cause a change in the wavelength, and as wavelength changes, various colors are generated.

The light's path difference is therefore generated as a result of the thickness variation of the soap bubble.

5 0

3 years ago