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Solnce55 [7]
3 years ago
13

What is the wavelength of a wave that has a speed of 26 m/s and a frequency of 49? ? Show your work

Physics
1 answer:
nirvana33 [79]3 years ago
6 0

Answer:

Wave speed = Wavelength x Frequency

26 m/s = Wavelength x 49

Divide by 49 to find the wavelength:

The wavelength is approximately 0.53

Let me know if this helps!

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Each of the two coils has 320 turns. The average radius of the coil is 6 cm. The distance from the center of one coil to the ele
Temka [501]

Answer:

Magnetic field, B=2.39\times 10^{-3}\ T

Explanation:

It is given that,

Number of turns, N = 320

Radius of the coil, r = 6 cm = 0.06 m

The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m

Current flowing through the coils, I = 0.5 A

We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :

B=\dfrac{\mu_oINr^2}{(x^2+r^2)^{3/2}}

B=\dfrac{4\pi \times 10^{-7}\times 0.5\times 320\times (0.06)^2}{(0.03^2+0.06^2)^{3/2}}

B = 0.00239 T

or

B=2.39\times 10^{-3}\ T

So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is 2.39\times 10^{-3}\ T. Hence, this is the required solution.

7 0
3 years ago
Which wave, A or B, has higher energy?
eduard

Answer:

Wave A.

Explanation:

The energy of a wave is directly proportional to the square of the amplitude.

If a wave has higher amplitude, it will have more energy. On the other hand, a wave having lower amplitude, it will have less eenergy.

In this case, we need to tell which wave has higher energy. Hence, the correct option is A because it has a higher amplitude.

8 0
3 years ago
Read 2 more answers
A large fake cookie sliding on a horizontal surface is attached to one end of a horizontal spring with spring constant k = 440 N
irinina [24]

Answer:

a) 0.275 m b) 13.6 J

Explanation:

In absence of friction, the energy is exchanged between the spring (potential energy) and the cookie (kinetic energy), so at any point, the sum of both energies must be the same:

E = ½ kx2 + ½ mv2

If we take as initial state, the instant when the cookie is passing through the spring’s equilibrium position, all the energy is kinetic, and we know that is equal to 20.0 J.

After sliding to the right, while is being acted on by a friction force, it came momentarily at rest. At this point, the initial kinetic energy, has become potential elastic energy, in part, and in thermal energy also, represented by the work done by the friction force.

So, for this state, we can say the following:

Ki = Uf + Eth = ½* k*d2 + Ff*d

20.0J = ½ *440 N/m* d2 + 11.0 *d, where d is the compressed length of the spring, which is equal to the distance travelled by the cookie before coming momentarily at rest.

We have a quadratic equation, that, after simplifying terms, can be solved as follows, applying the quadratic formula:

d = -0.05/2 +/- √0.090625 = -0.025 +/- 0.3 = 0.275 m (we take the positive root)

b) If we take as our new initial status the moment at which the spring is compressed, and the cookie is at rest, all the energy is potential:

E = Ui = 1/2 k d²

In this case, d is the same value that we got in a), i.e., 0.275 m (as the distance travelled by the cookie after going through the equilibrium point is the same length that the spring have been compressed).

E= 1/2 440 N/m . (0.275)m² = 16.6 J

When the cookie passes again through the equilibrium position, the energy will be in part kinetic, and in part, it will have become thermal energy again.

So, we can write the following equation:

Kf = Ui - Ff.d = 16.6 J - 11.0 (0.275) m = 16.6 J - 3.03 J = 13.6 J

3 0
3 years ago
Im bad at work problems can any one help with this problem ?
lyudmila [28]
We will put the number of trips in the first column, the miles driven in the second column and gallons of fuel used in the third column.

8    7,680    1,010
7    9,940    1,330
12  14,640  1,790
12  13,920  2,050
4 0
4 years ago
Is more of north america north or south of the tropic of cancer
TEA [102]

Explanation:

This parallel is located in the northern hemisphere, located at a latitude of 23 ° 26′12.2 ″ (or 23,43671 °) north of the equator. Approximately in the geographic half of Mexico, crossing the states of Baja California Sur, Sinaloa, Durango, Zacatecas, San Luis, Potosí, Nuevo León, Tamaulipas. Therefore, there is more of north america, at north of the tropic of cancer.

6 0
3 years ago
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