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Savatey [412]
3 years ago
14

At what altitude above the earth's surface would the acceleration due to gravity be 4.9 m/s^2? Assume the mean radius of the ear

th is 6.4x10^6 metres and the acceleration due to gravity 9.8m/s^2 on the surface of the earth.
Physics
1 answer:
Mandarinka [93]3 years ago
4 0
We apply the gravity calculation expressed in the formula: g=GM/r2 
where G is the gravitational constant, m is the mass and r is the radius
r=√GM/g
(1)       Radius = √6.674e-11*5.972e24/8             = 7058 kms    Earth radius or surface of earth from center of earth= 6400 kmsSo r= 658 kms from surface of earth.
Gravity 8m/s2 will be at 658 kms from surface of earth.
(2) half gravity= 9.8/2= 4.9 m/s2     Radius=√6.674e-11*5.972e24/4.9                 = 9019 kms        Half Gravity will exist at 9019-6400= 2619 kms from surface of earth.
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Answer:

x=0.478\ m is the compression in the spring

Explanation:

Given:

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<u>Now since the bullet-mass gets embed into the block, we apply the conservation of momentum as:</u>

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Now this kinetic energy of the combined mass gets converted into potential energy of the spring.

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\frac{1}{2} (M+m).v^2=\frac{1}{2} k.x^2

\frac{1}{2} \times (2+0.01)\times 1.4925^2=\frac{1}{2} \times 19.6\times x^2

x=0.478\ m is the compression in the spring

4 0
3 years ago
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Answer:

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F_y = 72.15 N

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F_x = 181.2 N

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