Answer:
The fractional Intensity 
= 0.0146
Given:
wavelength of the light, 
slit and screen separation difference, D = 130 cm = 1.3 m
distance of the point from the center of the principal maximum, y = 4.10 mm = 0.041 m
slit width, d = 0.420 mm = 
Solution:
To calculate the fractional intensity, we use the given formula:
(1)
For very small angle:
(2)
where
Using eqn (2):
Now, using eqn (1):
Replaces spring 2. the mass of the weight and pulley are unchanged: m=5.8 kg and mp=1.7 kg
Not sure the precise concept of "normal observation", but I assume that is observed by "eyes".
Eye observation is basically macroscopic, but when you use a mark, which can be regarded as a point of mass, then it goes to microscopic.
Mark is a reference point which you can compare the relative position change, but with your eyes, first you cannot notice microscopic changes, second the eyes cannot precisely set a stable reference point.
Answer:
1) W = 150 J
Explanation:
Work (W) is defined as the product of force F by the distance (d)the body travels due to this force.
W= F*d Formula ( 1)
The work is positive (W+) if the force has the same direction of movement of the object.
The work is negative (W-) if the force has the opposite direction of the movement of the object.
The component of the force that performs work must be parallel to the displacement.
Work done to lift the floor box to its final position
We apply the formula (1)
W= F*d
W = (100 N)*(1.5 m)
W = 150 J
Answer:
0.50027
Explanation:
ΔA=
Where ΔA is the change in area
There is a 2 since the coefficient for area = 2 x that for the linear coefficient
is the original area
is the coefficient of thermal expansion
And T is the change in temperature
ΔA=2(0.000009)(0.5)(30-0)=0.00027
New area= ΔA+ = 0.5+0.00027=0.50027
