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Artist 52 [7]
3 years ago
8

A crate of books rests on a level floor. To move it along the floor at a constant velocity, why do you exert less force if you p

ull it at an angle Ï above the horizontal than if you push it at the same angle below the horizontal?
Physics
1 answer:
Mademuasel [1]3 years ago
8 0

Answer:should be a matter of vector analysis.

Pulling above the horizontal has less surface area for the opposing friction

Explanation:

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How are dwarf planets different from true planets?
morpeh [17]

Answer:

The only difference between a planet and a dwarf planet is the area surrounding each celestial body. A dwarf planet has not cleared the area around its orbit, while a planet has.

Explanation:

the three criteria of the IAU for a full-sized planet are: It is in orbit around the Sun. It has sufficient mass to assume hydrostatic equilibrium (a nearly round shape). It has "cleared the neighborhood" around its orbit .

3 0
2 years ago
With a 900 V source, voltage is divided across 3 series resistors of 300 V, 280 V, and:
telo118 [61]

Answer:

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2 years ago
A draft is made of a plastic block with a density of 650kg/m^3, and its dimensions are 2.0mx3.0mx5.0m ,what is the raft's appare
mixas84 [53]
Weight in water = mass of block - mass of volume of displaced water
8 0
3 years ago
In a football game, the running back takes a handoff and begins running toward midfield at 3.21 yards/s . As he moves through hi
Inessa [10]

Given Information:

Initial speed = u = 3.21 yards/s

Acceleration = α  = 1.71 yards/s²

Final speed = v = 7.54 yards/s

Required Information:

Distance = s = ?

Answer:

Distance = s = 13.61

Explanation:

We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.

We know from the equations of motion,

v² = u² + 2αs

Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.

Re-arranging the above equation for distance yields,

2αs = v² - u²

s = (v² - u²)/2α

s = (7.54² - 3.21²)/2×1.71

s = 46.55/3.42

s = 13.61 yards

Therefore, the runner traveled a distance of 13.61 yards before being tackled.

8 0
3 years ago
34000×0.4<br> ----------------<br> 0.02×200<br> In scientific notation
VashaNatasha [74]

Answer:

the simplified expression is written as 3.4 x 10³

Explanation:

Given expression;

\frac{34000\times 0.4}{0.02 \times 200}

in scientific notation, the expression is simplified as;

\frac{34000\times 0.4}{0.02 \times 200}  = \frac{13600}{4} = 3400 = 3.4 \times 10^3

Therefore, in scientific notation, the simplified expression is written as 3.4 x 10³

4 0
2 years ago
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