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3 years ago

In which state does the precipitate exist in a precipitation reaction?

Chemistry

1 answer:

Sveta_85 [38]3 years ago

5 0

Answer: solid.

Explanation:

Precipitate is the solid substance produced during a chemical reaction carried out in a solution.

The precipitate is formed when the reactants in a chemical reaction, which are in solution, form a compound that is insoluble, and so it cannot stand dissolved but precipiates, normally going to the bottom of the vessel, in solid form.

The phases in a chemical equation are indicated using letters inside parenthesis placed to the right of the chemical formula of each compound or element.

These are the common uses: s for solid, aq for aqueous solution, l for liquid, and g for gaseous.

This is an example:

2 NaOH (aq) + CuCl₂ (aq) → 2 NaCl (aq) + Cu (OH)₂ (s)

The phases are:

Reactant side: NaOH and CuCl₂ are dissolved in water, which is indicated by the the word aq, meaning aqueous.
Product side: NaCl is aqueous, and Cu(OH)₂ is in solid form, meaning that it is a precipitate.

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3 years ago

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

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In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

Best regards.

8 0

3 years ago

A wood pole is 12 metres long and is cut into 5 equal sections. If each cut wastes 10 cm of pole, what length would each section

Sophie [7]

Each section would be 230 centimeters or 2.30 meters long.

<h3>Sectional division</h3>

The original wood pole is 12 meters long.

12 meters = 12 x 100 = 1200 centimeters

It is to be cut into 5 equal sections: 1200/5 = 240 centimeters

But each cut wastes 10 cm of the pole.

240 - 10 = 230 centimeters.

Thus, each section would be 230 centimeters or 2.30 meters long.

More on sectional divisions can be found here: brainly.com/question/15381501

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