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scZoUnD [109]
3 years ago
9

What is the pow of a solution that has a hydroxide ion concentration of 4.82 x 10-6 M?

Chemistry
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

pOH = 5.32

Explanation:

<em>What is the</em><em> pOH</em><em>...</em>

The pOH of a solution is defined as:

-log [OH⁻] <em>The -log of hydroxide ion concentration in molarity units</em>

It is used to find pH of a solution because: pH = 14-pOH

Thus, the pOH of the solution of the problem is:

pOH = -log [OH⁻] = -log [4.82x10⁻⁶M]

pOH = 5.32

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Answer:

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Answer:

\large \boxed{\text{-851.4 kJ/mol}}

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

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\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}

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