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2 years ago

What is the pow of a solution that has a hydroxide ion concentration of 4.82 x 10-6 M?

Chemistry

1 answer:

Likurg_2 [28]2 years ago

4 0

Answer:

pOH = 5.32

Explanation:

What is the pOH...

The pOH of a solution is defined as:

-log [OH⁻] The -log of hydroxide ion concentration in molarity units

It is used to find pH of a solution because: pH = 14-pOH

Thus, the pOH of the solution of the problem is:

pOH = -log [OH⁻] = -log [4.82x10⁻⁶M]

pOH = 5.32

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A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical formula? The second step is to calcul

Free_Kalibri [48]

Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.

2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O

1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O

Empirical formula
H2SO4

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2 years ago

Read 2 more answers

Consider the following reaction at constant pressure. Use the information provided below to determine the value of ΔS at 473 K.

Elis [28]

Answer:

The reaction will be spontaneous

Explanation:

To determine if the reaction will be spontaneous or not at this temperature, we need to calculate the Gibbs's energy using the following formula:

$\Delta G= \Delta H - T * \Delta S$

If the Gibbs's energy is negative, the reaction will be spontaneous, but if it's positive it will not.

Calculating the $\Delta G= -1267 - 473 K* \Delta S$ :

$\Delta G= -1267 - 473 K* \Delta S$

Now, other factor we need to determine is the sign of the S variation. When talking about gases, the more moles you have in your system the more enthropic it is.

In this reaction you go from 7 moles to 8 moles of gas, so you can say that you are going from one enthropy to another higher than the first one. This results in: $\Delta S>0[/tex}Back to this expression: [tex]\Delta G= -1267 - 473 K* \Delta S$

If the variation of S is positive, the Gibbs's energy will be negative always and the reaction will be spontaneous.

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3 years ago

In substitution reactions, (CH3)3C-I reacts at the same rate with Br- and Cl- even though Br- is a more reactive nucleophile tha

Kamila [148]

Answer:

A. (CH3)3C-I reacts by SN1 mechanism whose rate is independent of nucleophile reactivity.

Explanation:

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In SN1 mechanism, the rate of reaction depends solely on the concentration of the alkyl halide (unimolecular mechanism) and is independent of the concentration of the nucleophile. As a result of this, both Br^- and Cl^- react at the same rate.

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Which of the following characteristics helps to distinguish a biome?

ladessa [460]

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Explanation:

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The + symbol, on the products side, in a chemical equation means

malfutka [58]

Explanation:

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If it's helpful ❤❤

THANK YOU

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