Answer:
1.2029 J/g.°C
Explanation:
Given data:
Specific heat capacity of titanium = 0.523 J/g.°C
Specific heat capacity of 2.3 gram of titanium = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
1 g of titanium have 0.523 J/g.°C specific heat capacity
2.3 × 0.523 J/g.°C
1.2029 J/g.°C
Answer:
18 liters
Explanation:
Step 1: Figure out what the formula and what you are dealing with.
- 25 degrees celcius is constant, so it is irrelevant for the mathmatical part.
- P1 = 1 atm
- P2 = 20 atm
- V1 = 360 liters
- V2 = trying to find
Note: remember the original equation is V1/P1 = V2/P2
- Step 2: Rearrange the equation to fit this problem, you should get...
V2 = V1 x P1 / P2
- Step 3: Fill our own numbers in. You should get...
360 L x 1 atm / 20 atm = 18 Liters (do the math)
- Answer = 18 Liters
- Remember to just follow the formula and fill it in with your own numbers.
If you need any more help comment below. I am happy to help anytime.
Answer:
-Warm air sinks, creating an area of low pressure.
Explanation:
Heat will weigh more, than cool air!
Since plants turn sunlight into glucose (sugar) that humans and animals eat... the energy we get from our food comes indirectly from the sunlight.
Answer:
Heat transfer in step 2 = 47.75 J
Explanation:
Internal energy = heat + work done
U = Q + W
In a cyclic process the total internal energy change of the system = 0.
In the process there are two steps. The total heat exchange in the process is the sum of heat exchanges in the two processes.
We have to find the heat exchange in step 2.
In step 1,
W = 1.25 J Q = -37 J
= -37 + 1.25 = -35.75 J
In step 2, the internal energy change will be negative of that in step 1.
U = 35.75 J
W = -12 J
U = Q + W
35.75 = Q -12
Q = 47.75 J
Heat transfer in step 2 = 47.75 J
