An item costs $380 before tax and the sales tax is $7.60 find the sales tax rate write your answer as a percentage

Which expression is equal to – 8s – 2s2 + 23s – 4?

vovangra [49]

Answer:

15s-2s^2-4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The point A (-7,5) is reflected over the line x = -5, and then is reflected over the line x= 2. What are the coordinates of

liubo4ka [24]

Answer:

(7, 5) is the final reflection of the point.

Step-by-step explanation:

We are given point A(-7, 5) which is first reflected over the line $x= -5$ .

The minimum distance of the point A(-7, 5) from the line $x= -5$ is 2 units across the horizontal path (No change in y coordinate).

Point A lies 2 units on the left side of the line $x= -5$ .

So, its reflection will be 2 units on the right side of $x= -5$ .

Let its reflection be A' which has coordinates as (-5+2,5) i.e. (-3, 5).

Now A'(-3, 5) is reflected on the line $x=2$ .

The minimum distance of the point A'(-3, 5) from the line $x=2$ is 5 units across the horizontal path (No change in y coordinate).

Point A' lies 5 units on the left side of the line $x=2$ .

So, its reflection will be 5 units on the right side of $x=2$ .

Let its reflection be A'' which has coordinates as (2+5, 5) i.e (7, 5) is the final reflection of the point..

Please find attached image.

(7, 5) is the final reflection of the point.

5 0

3 years ago

What number represents 1 tens and 18 ones

melamori03 [73]

Answer:

18.1

Step-by-step explanation:

8 0

4 years ago

Check the true statements below:

valentinak56 [21]

Answer:

a) False

b) False

c) True

d) False

e) False

Step-by-step explanation:

a. A single vector by itself is linearly dependent. False

If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.

b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False

A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.

c. The columns of an invertible n × n matrix form a basis for Rⁿ. True

If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.

d. In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False

Row operations can not affect linear dependence among the columns of a matrix.

e. A basis is a spanning set that is as large as possible. False

A basis is not a large spanning set. A basis is the smallest spanning set.

3 0

3 years ago

Let sin A= -3/5 with 270°< A< 360°. Find the following. sin A/2

GREYUIT [131]

Answer:

1/sqrt10

Step-by-step explanation:

1) Find out cosA using formula (cosA)^2+(sinA)^2=1

The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5

So cosA=-4/5 or cosA=4/5.

Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.

2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.

(sinA/2)^2= 0.1

sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10

But 270°< A< 360°, then 270/2°<A/2<360/2°

135°<A/2<180°, so sinA/2 must be positive and the only correct answer is

sin A/2= 1/sqrt10

6 0

3 years ago