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nevsk [136]
3 years ago
15

M3+ 3 m3 + 4 m²simplify​

Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

{m}^{3}  +  {27}^{m}  + 4 {m}^{2}

Step-by-step explanation:

{m}^{3}  +  {3}^{m 3}  + 4 {m}^{2}

{m}^{3}  +  {3}^{m \times 3}  + 4 {m}^{2}

{m}^{3}  +  {3}^{3m}  + 4 {m}^{2}

{3}^{3m}  =  ({3}^{3}  {)}^{m}  =  {27}^{m}

➡️ {m}^{3}  +  {27}^{m}  + 4 {m}^{2}

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The distance traveled varies directly with the time spent in motion when speed is held constant.
disa [49]

Answer:

16/3 or 5.3

Step-by-step explanation:

150 miles  = 4 hours

Find how long it takes to travel 50 miles(GCF  between 150 and 200)

150/3 = 4/3

50 miles = 1 1/3 hours: multiply by 4 to get 200 miles

50 x 4 = 4/3 x 4/1

200 = 16/3

16/3 hours or 5.3

7 0
3 years ago
For every 3 presents lisa wrapped, helen wrapped 5. if they wrapped a total of 184 how many did each wrap. ( how did you get the
igor_vitrenko [27]
3 : 5.....thats ur ratio...added = 8...so basically, Lisa wrapped 3 out of 8 (or 3/8) and Helen wrapped 5 out of 8 (or 5/8)

3/8(184) = 552/8 = 69 : Lisa wrapped 69
5/8(184) = 920/8 = 115 : Helen wrapped 115
6 0
3 years ago
Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
**HELP!**
mr_godi [17]
If two figures or lengths are similar, then the ratios of the corresponding lengths are equal.
Thus, 8/32 =5/x
          8x = 160
            x = 20 feet
Therefore, the length of the flag pole was 20 feet long
3 0
3 years ago
Enter a related multiplication sentence to solve 1/6 divided by 3
goldfiish [28.3K]

Answer:

0.05555555555

Step-by-step explanation:

usless you flip it around then it would be 2 cause 1/6 / 3 = .0555555555555 because the 1/6 butif they want u to flip it then it would be 6/3=2

6 0
3 years ago
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