68 is the 22nd term of the following sequence.
<u>Step-by-step explanation:</u>
- The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the Arithmetic progression ( AP).
- For finding the nth term in the AP we have a formula tn = a + (n-1) × d
- Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
- Thus here tn = 5 + ( 22 - 1 ) × 3.
- On subtracting we get tn = 5 + (21 ) × 3
- On multiplying we get tn = 5 + 63
- After adding we get tn = 68. It is the 22nd term in the given series.
Answer:
0.16
Step-by-step explanation:
if the number in the thousandths is 5 or over you round it up.
Answer: 6.7*10^-5
Step-by-step explanation:
