Answer: AB = 12.5, BC = 15
<u>Step-by-step explanation:</u>
Perimeter of ΔBCD = BC + CD + BD. Since it is an isoceles triangle, then BC = CD = BD. So, Perimeter of ΔBCD = 3BC
3BC = 45
<u>÷3 </u> <u>÷3 </u>
BC = 15
Perimeter of ΔABC = AB + BC + AC. Since it is an isosceles triangle with BC as the base, then AB = AC. So, Perimeter of ΔABC = 2AB + BC
2AB + BC = 40
2AB + 15 = 40
<u> -15</u> <u> -15 </u>
2AB = 25
<u>÷2 </u> <u>÷2 </u>
AB = 12.5
Answer:
The equation for finding the hypotenuse is:
c^2+c^2=h^2
For example, in the first exercise:
8^2+10^2=164^2
For clearing the equation, find out the root of 164=
12.8
Hypotenuse of the first triangle is 12.8!
Let me help you with the next, if you still dont get it:
8^2+13^2=233^2
Root of 233: 15.2
Hypotenuse of second triangle is 15.2!
Answer:
6.0042
Step-by-step explanation:
6 and forty-two ten-thousandths as a decimal.
mixed number : 
decimal : 6.0042
The answer is 525, meaning it’s more than it should be, hope i helped!
