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3 years ago

Please help asap!!! Need an accurate anwser to hand this assignment in!

Mathematics

1 answer:

fomenos3 years ago

3 0

I would help but my accuracy is under 13% in fortnite

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The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago

Find the maximum value of the function f(x) = -1.9x^2 + 24x – 71.3 to the<br> nearest hundredth.

d1i1m1o1n [39]

Being that the system is quadratic—with parabola opening downwards—you’re going to need to find the vertex. You can find the x coordinate of the vertex with -b/2a . Then plug in for x to find the y coordinate…

4 0

2 years ago

The length of a rectangle is stored in a double variable named length, the width in one named width. Write an expression whose v

myrzilka [38]

Answer:

Answered

Step-by-step explanation:

Length is stored in variable named length

the width in one named width

the expression for the diagonal of the rectangle can be written as

double diagonal = Math.sqrt(Math.pow(length,2) + Math.pow(width,2))

8 0

3 years ago

34) -3(5 + 2x) - 7<br> distribute

vitfil [10]

Answer:

-22-6x

Step-by-step explanation:

Multiply, leave -7 out. Then combine like terms.

5 0

2 years ago

Read 2 more answers

Problem 2. Smasher Van bound for Koronadal City leaves Polomolok every 15 minutes

astraxan [27]

Answer:

5. c. Every 1 hour

6. c. 4 times

7. b. 3 times

Step-by-step explanation:

The given parameters of the rate of departure of the two vans are;

The rate of departure of Smasher Van bound for Koronadal City = Every 15 minutes

The rate of departure of Nustafa Van= Every 20 minutes

5. The time, 'x', when the two vans leave at the same time is given by the Lowest Common Multiple (LCM) of 15 and 20 as follows;

Multiples of 15 = 15, 30, 45, 60

Multiples of 20 = 20, 40, 60

Therefore, the LCM of 15 and 20 = 60

The time, when the two vans leave at the same time = Every 60 minutes = Every 1 hour

The time, when the two vans leave at the same time = Every 1 hour

6. The number of times the Smasher Van leaves Polomolok so that the two vans leave together is given by the number of multiples 15 minutes in 60 minutes = 60 minutes/(15 minutes) = 4 times

7. The number of times the Nustafa Van leaves Polomolok so that the two vans leave together is given by the number of multiples 20 minutes in 60 minutes = 60 minutes/(20 minutes) = 3 times.

7 0

3 years ago