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larisa [96]
3 years ago
10

The radar system of a navy cruiser transmits at a wavelength of 2.0 cm, from a circular antenna with a diameter of 2.0 m. At a r

ange of 7.8 km, what is the smallest distance in meters that two speedboats can be from each other and still be resolved as two separate objects by the radar system?
Physics
1 answer:
Snezhnost [94]3 years ago
6 0

Answer:

95.16 m

Explanation:

L = Range of radar = 7.8 km

\lambda = Wavelength = 2 cm

d = Diameter of antenna = 2 m

D = Distance

We have the relation

\dfrac{D}{L}=1.22\dfrac{\lambda}{d}\\\Rightarrow D=1.22\dfrac{L\lambda}{d}\\\Rightarrow D=1.22\dfrac{7800\times 0.02}{2}\\\Rightarrow D=95.16\ m

The smallest distance in meters that two speedboats can be from each other and still be resolved as two separate objects by the radar system is 95.16 m

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Calculate the Poynting vector at the surface of the filament, associated with the static electric field producing the current an
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We anticipate a constant Poynting vector of magnitude since the hot resistor will be emitting heat and none of the electric or magnetic fields will change over time.

S = P/A

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Always pointing away from the wire, this Poynting vector.

<h3>What is the Poynting vector?</h3>

Describes the size and direction of the energy flow in electromagnetic waves using a Poynting vector. It bears the name of the 1884 invention of English physicist John Henry Poynting. It stands for the electromagnetic field's directional energy flux or power flow. The Poynting vector is significant in a static electromagnetic field because it determines the direction of energy flow in an electromagnetic field. This vector represents the radiation pressure of an electromagnetic wave and points in its direction of propagation.

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1 year ago
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Taya2010 [7]

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8 0
3 years ago
A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
6) A stone is thrown vertically upward and returns to its starting position in o 5 s,What was its initial velocity?
NikAS [45]
25m/s if you are using -10 as gravity
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