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Firdavs [7]
4 years ago
11

You have a 90 W electrical appliance that is on 24 hours per day. At $0.51 per kWh, how much are you paying daily for electricit

y to operate this appliance?
Show your calculations here:
Physics
1 answer:
Iteru [2.4K]4 years ago
6 0

90 watts = 0.09 KW

Energy = (power) x (time) =
                  (0.09) x (24) KWh

Cost = (energy) x (unit price) =
           (0.09 x 24) x ($0.51) = <em>$1.10</em> per day (rounded)

(Those are very expensive kWh's.)


You might be interested in
Describe different types of motion with examples. (4)
Illusion [34]

Answer:

a)

there r two types of motion, uniform and non-uniform

uniform means equal distance travelled at equal intervals of time

and non-uniform is exactly the opposite.

b)

quantities which can be represented by magnitude along r called scalar quantities such as speed.

quantities which need magnitude along with direction r called vector quantities such as velocity.

c)

velocity=10m/s

acceleration = u-v/s i.e initial final velocity - initial velocity upon time

acceleration= 0.2m/s sq

time= 30s

10 = displacement/time

10 = x/30

10 = 300

Answer is 300 meters - distance/displacement.

8 0
3 years ago
Read 2 more answers
In the attached position versus time graph what is the magnitude of average velocity for the entire 19 seconds of the motion. An
evablogger [386]

According to the plot, the positions at time <em>t</em> = 0 s and <em>t</em> = 19 s are -1 m and -2 m, respectively. So the average velocity for the 19-s interval is

v_{\rm ave} = \dfrac{-2\,\mathrm m - (-1\,\mathrm m)}{19\,\mathrm s} = -\dfrac1{19}\dfrac{\rm m}{\rm s}\approx \boxed{-0.05\dfrac{\rm m}{\rm s}}

8 0
3 years ago
3. The driver of a blue car is moving at a speed of 35 mph. A red car passes him at a speed of
faust18 [17]
The blue car is moving with a velocity of -14 m/s using the red car as a reference frame.
8 0
3 years ago
What do all waves, including sound and light, have in common​
Schach [20]

Answer:

They all have frequency, wavelength, amplitude, speed and also all transfer energy.

6 0
3 years ago
What is the de Broglie wavelength of an electron that strikes the back of the face of a TV screen at 1/10 the speed of light? __
Softa [21]

Answer: 2.42(10)^{-11} m

Explanation:

The de Broglie wavelength \lambda is given by the following formula:

\lambda=\frac{h}{p}   (1)

Where:

h=6.626(10)^{-34}\frac{m^{2}kg}{s} is the Planck constant

p is the momentum of the atom, which is given by:

p=m_{e}v_{e}   (2)

Where:

m_{e}=9.11(10)^{-31}kg is the mass of the electron

v=\frac{1}{10}c is the velocity of the electron (we are told it is 1/10 the speed of light c=3(10)^{8}\frac{m}{s})

This means equation (2) can be written as:

p=m_{e}\frac{1}{10}c   (3)

Substituting (3) in (1):

\lambda=\frac{h}{m_{e}\frac{1}{10}c}    (4)

\lambda=10\frac{h}{m_{e} c}    (5)

Now, we only have to find \lambda:

\lambda=10\frac{6.626(10)^{-34}\frac{m^{2}kg}{s}}{(9.11(10)^{-31}kg)(3(10)^{8}\frac{m}{s})}     (6)

<u>Finally:</u>

\lambda=2.42(10)^{-11} m>>> This is the de Broglie wavelength of an electron.

6 0
4 years ago
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