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Firdavs [7]
4 years ago
11

You have a 90 W electrical appliance that is on 24 hours per day. At $0.51 per kWh, how much are you paying daily for electricit

y to operate this appliance?
Show your calculations here:
Physics
1 answer:
Iteru [2.4K]4 years ago
6 0

90 watts = 0.09 KW

Energy = (power) x (time) =
                  (0.09) x (24) KWh

Cost = (energy) x (unit price) =
           (0.09 x 24) x ($0.51) = <em>$1.10</em> per day (rounded)

(Those are very expensive kWh's.)


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Answer:

2.27\cdot 10^{49}

Explanation:

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where

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F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N

The electrical force between the proton and the electron is given by

F_E=k\frac{q_p q_e}{r^2}

where

k is the Coulomb constant

q_p = q_e = q is the elementary charge (charge of the proton and of the electron)

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N

So, the ratio of the electrical force to the gravitational force is

\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}

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5 0
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Answer:

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