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Firdavs [7]
3 years ago
11

You have a 90 W electrical appliance that is on 24 hours per day. At $0.51 per kWh, how much are you paying daily for electricit

y to operate this appliance?
Show your calculations here:
Physics
1 answer:
Iteru [2.4K]3 years ago
6 0

90 watts = 0.09 KW

Energy = (power) x (time) =
                  (0.09) x (24) KWh

Cost = (energy) x (unit price) =
           (0.09 x 24) x ($0.51) = <em>$1.10</em> per day (rounded)

(Those are very expensive kWh's.)


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You breathe in more oxygen than you breathe out. And you breathe out more carbon dioxide than you breathe in.
AlladinOne [14]

Answer:

B. chemical only.

Explanation:

In the process of respiration which is a chemical process where organic compound is released. In this process exergonic reaction takes place in which compound changes into different ones.

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3 0
3 years ago
A 0.49-kg cord is stretched between two supports,7.3m apart. When one support is struck by a hammer, a transverse wave travels d
Wewaii [24]

Answer:

T= 5.18N

Explanation:

u = mass of chord / length of chord

u = 0.49/ 7.3

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v = 7.3 / 0.83 = 8.795m/s

Tension is calculated below using the formula

T = v² * u

T = (8.795)² x 0.067

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The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th
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Read 2 more answers
n deep space, sphere A of mass 47 kg is located at the origin of an x axis and sphere B of mass 110 kg is located on the axis at
Volgvan

Answer:

a)-1.014x 10^{-7J

b)3.296 x  10^{-7J

Explanation:

For Sphere A:

mass 'Ma'= 47kg

xa= 0

For sphere B:

mass 'Mb'= 110kg

xb=3.4m

a)the gravitational potential energy is given by

U_{i = -GMaMb/ d

U_{i= - 6.67 x 10^{-11} x 47 x 110/ 3.4 => -1.014x 10^{-7J

b) at d= 0.8m (3.4-2.6) and U_{i=-1.014x 10^{-7J

The sum of potential and kinetic energies must be conserved as the energy is conserved.

K_{i + U_{i= K_{f + U_{f

As sphere starts from rest and sphere A is fixed at its place, therefore K_{i is zero

U_{i= K_{f + U_{f

The final potential energy is

U_{f= - GMaMb/d

Solving for 'K_{f '

K_{f = U_{i + GMaMb/d => -1.014x 10^{-7 + 6.67 x 10^{-11} x 47 x 110/ 0.8

K_{f = 3.296 x  10^{-7J

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