Answer:
the velocity of car when it passes the truck is u = 16.33 m/s
Explanation:
given,
constant speed of truck  = 28 m/s
acceleration of car = 1.2 m/s²
passes the truck in 545 m 
speed of the car when it just pass the truck = ?
time taken by the truck to travel 545 m
               time = 
 
               time = 
 
               time =19.46 s
velocity of the car when it crosses the truck


u = 16.33 m/s
the velocity of car when it passes the truck is u = 16.33 m/s
 
        
             
        
        
        
Around 27 satelites is used for GPS technology
        
                    
             
        
        
        
Answer:
≅50°
Explanation:
We have a bullet flying through the air with only gravity pulling it down, so let's use one of our kinematic equations:
Δx=V₀t+at²/2
And since we're using Δx, V₀ should really be the initial velocity in the x-direction. So:
Δx=(V₀cosθ)t+at²/2
Now luckily we are given everything we need to solve (or you found the info before posting here):
- Δx=760 m
- V₀=87 m/s
- t=13.6 s
- a=g=-9.8 m/s²; however, at 760 m, the acceleration of the bullet is 0 because it has already hit the ground at this point!
 With that we can plug the values in to get:




 
        
             
        
        
        
Carbon dioxide and water :) hope this helped!
        
                    
             
        
        
        
Explanation:
i) center of gravity (or mass)
ii) m = W/g = (160 N)/(9.8 m/s^2)
 = 16.3 kg