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Phantasy [73]
3 years ago
12

What is the DISPLACEMENT of the motorbike rider in the picture?

Physics
1 answer:
lutik1710 [3]3 years ago
6 0
120m north east hope this helps
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How do the individual forces compare when the rider experiences a sensation being lighter than his normal weight ? What is the a
shusha [124]

Answer:

When the elevator is accelerating downward, the person feels lighter due to the downward normal force being less than the person's weight.

Explanation:

A person riding in an elevator subjected to a series of unbalanced forces depending on the direction the elevator is travelling.

Two forces are acting on the person; the force of gravity and the upward normal force from the elevator.

When the elevator is going upwards with acceleration a, the person feels heavier than his normal weight, due to the upward normal force being greater than the person's weight. N = mg + ma

When the elevator is moving downwards with acceleration a, the person feels lighter due to the downward normal force being less than the person's weight. N = mg - ma

However, when the elevator is moving up or down at constant velocity ie. acceleration a = 0, the person experience a normal force equal to weight. N = mg

When the elevator is moving downwards with acceleration a = g, the person experiences weightlessness. N = (mg - mg) = 0

6 0
3 years ago
A 0.0382-kg bullet is fired horizontally into a 3.78-kg wooden block attached to one end of a massless, horizontal spring (k = 8
wel

Answer:

280.87 ms⁻¹

Explanation:

Consider the motion of the bullet-block combination after collision

m = mass of the bullet = 0.0382 kg

M = mass of wooden block = 3.78 kg

V = velocity of the bullet-block combination after collision

k = spring constant of the spring = 833 N m⁻¹

A = Amplitude of oscillation = 0.190 m

Using conservation of energy

Kinetic energy of  bullet-block combination after collision = Spring potential energy gained due to compression of spring

(0.5)(m + M)V^{2} = (0.5)kA^{2}

(0.0382 + 3.78)V^{2} = (833)(0.190)^{2}

V = 2.81 ms⁻¹

v_{o} = initial velocity of the bullet before striking the block

Using conservation of momentum for the collision between bullet and block

m v_{o} = (m + M) V

(0.0382) v_{o} = (0.0382 + 3.78) (2.81)

v_{o} = 280.87 ms⁻¹

7 0
3 years ago
Which kind of wave moves back and forth along the direction of the wave?.
Jlenok [28]
The kind of wave it is Longitudinal
4 0
3 years ago
Which of the following can influence one???s ability to detect stimuli and increase one???s responsiveness to stimuli in dangero
kozerog [31]
The answer is B. Response Criteria
I hope this helps!!
5 0
3 years ago
Read 2 more answers
If forces acting on an object are unbalanced, which factor may result from an unbalanced force? The net force is negative. There
Oksi-84 [34.3K]

Answer:the Forces cancel out each other

Explanation:the forces cancel out each other

6 0
3 years ago
Read 2 more answers
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