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3 years ago

6) A stone is thrown vertically upward and returns to its starting position in o 5 s,What was its initial velocity?

Physics

1 answer:

NikAS [45]3 years ago

3 0

25m/s if you are using -10 as gravity

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f a single circular loop of wire carries a current of 45 A and produces a magnetic field at its center with a magnitude of 1.50

Lelu [443]

Answer:

Radius of the loop is 0.18 m or 18 cm

Explanation:

Given :

Current flowing through the wire, I = 45 A

Magnetic field at the center of the wire, B = 1.50 x 10⁻⁴ T

Number of turns in circular wire, N = 1

Consider R be the radius of the circular wire.

The magnetic field at the center of the current carrying circular wire is determine by the relation:

$B=\frac{N\mu_{0} I}{2R}$

Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ Tm/A.

Substitute the suitable values in the above equation.

$1.50\times10^{-4} =\frac{4\pi \times10^{-7}\times45 }{2R}$

R = 0.18 m

4 0

3 years ago

A particle (charge = 40 μC) moves directly toward a second particle (charge = 80 μC) which is held in a fixed position. At an in

lisov135 [29]

Answer:

The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m

Explanation:

Given that,

First charge = 40 μC

Second charge = 80 μC

Distance between the two particles = 2.0 m

Kinetic energy = 16 J

We need to calculate the distance separating the two particles when the moving particle is momentarily stopped

Using conservation of energy

$K.E+\dfrac{kq_{1}q_{2}}{d}=\dfrac{kq_{1}q_{2}}{x}+K.E$

Put the value into the formula

$16+\dfrac{9\times10^{9}\times40\times10^{-6}\times80\times10^{-6}}{2}=\dfrac{9\times10^{9}\times40\times10^{-6}\times80\times10^{-6}}{x}+0$

$16+14.4=\dfrac{28.8}{x}$

$30.4x=28.8$

$x=\dfrac{28.8}{30.4}$

$x=0.947\ m$

Hence, The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m

8 0

3 years ago

How many coulombs of charge do 50 * 10^31 electrons possess

Angelina_Jolie [31]

Quantity of Charge , Q = ne
Where n = number of electrons
e = charge on one electron = -1.6 * 10 ^-19 C.
n = 50 * 10^31 electrons

Q = (50 * 10^31)*( -1.6 * 10 ^-19 ) = -8 * 10^13 C.

Note that the minus sign indicates that the charge is a negative charge.

7 0

4 years ago

What is the acceleration of a 100-kg mass that has a force of 50 n acting on it?

Andrei [34K]

F=ma
50=100a
a=50/100
a=0.5 m/s^2

6 0

3 years ago

.Imagine that you pushed a box, applying a force of 60 newtons, over a distance of 4 meters. how much work have you done? 15 jou

DaniilM [7]

Work=force X distance
Newtons is a measurement of force
4 meters is your distance 60×4=240

240 joules

5 0

3 years ago

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