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Mars2501 [29]
2 years ago
6

A certain automobile is 6.0 m long if at rest. If it is measured to be 4.8 m long while moving, its speed is:

Physics
1 answer:
tatuchka [14]2 years ago
7 0

Answer:

1.8*10^8m/s

Explanation:

Using

L= lo√1-v²/c²

So making v subject we have

V= c√1-4.8²/6²

V= 0.6*c

V= 0.6*3E8m/s

V= 1.8*10^8m/s

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If an object starts at rest and moves 90 meters south along a straight line for 3 seconds, what is its average velocity?
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005 (part 1 of 2) 10.0 points
Anton [14]

A constant speed motion is one in which equal distances are covered in equal times

The bird travels a cumulative distance of 7.\overline 3 km

The reason the above value is correct is as follows:

The known parameters are;

Speed of the runner, v_r = 2.1 km/hr

The location where the bird begins to fly to the finish line = When the runner is 4.4 km from the finish line

The speed of the bird, v_b = 10.5 km/hr = 5 times the runners speed

The bird reaches the finish line, turns, and returns back to the runner

Required:

The find cumulative distance traveled by the bird

Solution:

The distance the bird travels is five times the distance the runner travels, therefore,

Let <em>x</em> represent the distance the runner ravels before the bird returns, we have;

The distance the bird travels = 4.4 + 4.4 - x = 8.8 - x

The distance the runner travels = x

The time the runner runs <em>x</em> km = The time the bird flies (8.8 - 4) km

From \ velocity = \dfrac{Distance }{Time}, we have;

Time= \dfrac{Distance }{Velocity}

Given the time taken by the runner is equal to the time taken by bird, while running, we have;

Time= \dfrac{x}{2.1} = \dfrac{8.8 - x}{10.5}

Therefore;

10.5·x = 2.1·(8.8 - x) = 2.1×8.8 - 2.1·x

10.5·x + 2.1·x =  2.1×8.8 = 18.84

12.6·x = 18.84

x = \dfrac{18.84}{12.6} =\dfrac{22}{15} = 1.4 \overline 6

The \ distance \  the \  bird \ travels = 8.8 - \dfrac{22}{15} \approx \dfrac{22}{3} = 7. \overline 3

<u>The cumulative distance the bird travels is 7.</u>\overline 3<u> km</u>

Learn more about constant speed motion here:

brainly.com/question/12684433

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1 year ago
What are the two main processes carried out by the excretory system?​
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Water and carbon dioxide
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3 years ago
If a star’s radiation peaks in the ultraviolet region of the spectrum, what could you conclude?
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The short answer is "it is a very intense star." 
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3 years ago
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a uniform rod of length 1.5m is placed over a wedge at 0.5m from one end .a force of 100 N is applied at its one end near the we
andreev551 [17]

Explanation:

The rod is uniform, so the center of gravity is at the center, or 0.75 m from the end.  The wedge is 0.5 m from the end, so the center is 0.25 m from the wedge.

Sum the torques about the wedge (it may help to draw a diagram first).  Take counterclockwise to be positive.

∑τ = Iα

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Sum the forces in the y direction.

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8 0
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