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GalinKa [24]
4 years ago
12

Question 16 of 20

Physics
1 answer:
marysya [2.9K]4 years ago
6 0
D. Only B and C
Medium and High levels can be harmful. But low even levels aren't good either.
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A body is moving with velocity 30 m pr sec Wt will b the distance covered by a body in 1 sec??
madam [21]

Answer:

30 metres

Explanation:

The velocity is 30m/s and the time is one second.

Distance =Velocity×time..

Distance=30m/s×1 second

=30×1

=30 metres

6 0
3 years ago
Pls help‼️‼️I have no idea how to solve this question... Can someone pls help! :(
sdas [7]

Answer: Its dragon ball bro

Explanation: (To Ship Leesoo) "My name is Twenty-Fifth Baam. For short you can just call me Baam. Even if you tell me to introduce myself, there's not much to say. I don't have parents... or a home... a single set of dirty clothes is all I have. I always thought that I might die alone without ever being able to do anything... But now- I have friends. Thank you."[45]

(Response when put in a danger of death situation) "There is something I fear more than death."[46][47]

(To Androssi Zahard) "The heart moves where the heart wills."[48]

(To Yu Han Sung) "If Rachel isn't up there, that place is nothing more than a pile of garbage. No matter what's up there, that won't change. You told me that being like I am is strange, but to me, you're a person who can't even find a single thing that's precious within that huge pile of garbage."[49]

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PART II

7 0
4 years ago
Read 2 more answers
How is 6.3 written in scientific notation? 6.3 mc022-1.jpg 100 63 mc022-2.jpg 10–1 6.3 mc022-3.jpg 101 63 mc022-4.jpg 100
hodyreva [135]
Not sure we can open those image files, but I think it would be 6.3*10^0
6 0
4 years ago
Read 2 more answers
¿ Cuáles son los principales aportes de las ciencias en el desarrollo del mundo? Menciona una aplicación de Física del contenido
maria [59]

Answer:earth, water, air, fire, and (later) aether, which were proposed to explain the nature and complexity of all matter in terms of simpler substances.

Explanation:

3 0
3 years ago
A motorcyclist goes around an un-banked (i.e., flat) circular turn of radius 31m, at a constant speed of 110km/hr (convert this
shepuryov [24]

Answer:

\mu_{s} = 3.071

This result represents an absurd, not plausible, as coefficient of frictions from materials have values between 0 and 1.

Explanation:

From Second Newton's Law we understand that centripetal acceleration experimented by motocyclist is due to force derived from static friction. And normal force of the ground on motocyclist equals weight of motocyclist due to the flatness of circular turn. The equations of equilibrium of the motocyclist is:

\Sigma F_{x} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R} (Eq. 1)

\Sigma F_{y} = N-m\cdot g = 0 (Eq. 2)

Where:

\mu_{s} - Static coefficient of friction, dimensionless.

N - Normal force, measured in newtons.

m - Mass of the motocyclist, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

v - Speed of the motorcyclist, measured in meters per second.

R - Radius of the circular turn, measured in meters.

The static coefficient of friction is cleared in (Eq. 1):

\mu_{s} = \frac{m\cdot v^{2}}{N\cdot R}

From (Eq. 2) we get that normai force is:

N = m\cdot g

And we expand the resulting expression in (Eq. 1):

\mu_{s} = \frac{m\cdot v^{2}}{m\cdot g\cdot R}

\mu_{s} = \frac{v^{2}}{g\cdot R} (Eq. 3)

If we know that v = 30.556\,\frac{m}{s}, g = 9.807\,\frac{m}{s^{2}} and R = 31\,m, the expected static coefficient of friction is:

\mu_{s} = \frac{\left(30.556\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (31\,m)}

\mu_{s} = 3.071

This result represents an absurd, not plausible, as coefficient of frictions from materials have values between 0 and 1.

4 0
3 years ago
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