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2 years ago

Name the fields which are balanced at a neutral point.

1 answer:

8 0

Productive because the field of vision on the balanced takes the neutral point in the fields with a different spacing adding it to fuse like wood

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Which of these quantities is constant in uniform circular motion?

zvonat [6]

The answer is A, speed

3 0

3 years ago

A cyclotron designed to accelerate protons has a magnetic field of magnitude 0.15 T over a region of radius 7.4 m. The charge on

klio [65]

Explanation:

It is given that,

Magnetic field, B = 0.15 T

Charge on a proton, $q=1.60218\times 10^{-19}\ C$

Mass of a proton, $m=1.67262 \times 10^{-27}\ kg$

The cyclotron frequency is given by :

$f=\dfrac{qB}{2\pi m}$

$f=\dfrac{1.60218\times 10^{-19}\ C\times 0.15\ T}{2\pi \times 1.67262 \times 10^{-27}\ kg}$

f = 2286785.40 Hz

$\omega=14368296.44\ rad/s$

$\omega=1.43\times 10^7 rad/s$

Hence, this is the required solution.

8 0

3 years ago

I’m not sure how to solve this

spayn [35]

Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

6 0

3 years ago

what is the period of a sound wave whose wavelength is 20.0m? use values from the book and show all of your work

Lera25 [3.4K]

The wavelength of a sound wave is related to its frequency by the relationship:
$f= \frac{v}{\lambda}$
where
f is the frequency
v is the speed of the wave
$\lambda$ is the wavelength

The wave in our problem has wavelength of $\lambda=20.0 m$ and speed of $v=343 m/s$ (this is the speed of sound in air), therefore its frequency is
$f= \frac{343 m/s}{20.0 m}=17.15 Hz$

And the period of the wave is equal to the reciprocal of its frequency:
$T= \frac{1}{f}= \frac{1}{17.15 Hz}=0.058 s$

5 0

4 years ago

What is the energy of an electromagnetic wave that has a frequency of 5.0 * 10^5 Hz? Use the equation E=hf, where h=6.626 * 10^-

AfilCa [17]

Answer:

3.3*10^-28j

Explanation:

A P E X

3 0

3 years ago

Name the fields which are balanced at a neutral point.​

Name the fields which are balanced at a neutral point.