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mel-nik [20]
3 years ago
14

An unbalanced force of 500 N is applied to a 75 kg object. What is the acceleration of the object?

Physics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

Acceleration, a=6.66\ m/s^2

Explanation:

Given that,

Force acting on the object, F = 500 N

Mass of the object, m = 75 kg

We need to find the acceleration of the object. The force acting on the object is given by :

a=\dfrac{F}{m}

a=\dfrac{500\ N}{75\ kg}

a=6.66\ m/s^2

So, the acceleration of the object is 6.66\ m/s^2. Hence, this is the required solution.

NemiM [27]3 years ago
7 0

1. Define Newtons second law of motion (this will help put things into perspective)

2.Get the mass of the object (in this case 75 kg)

3.The net force acting on the object...find it (in this case 500 N)

4.Change the equation to F=ma (500=75a)

5.Divide both sides by 75 and that is the acceleration.

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A beam of light has a wavelength of 620 nm in vacuum.
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Explanation:

It is given that,

Wavelength of a beam of light in vacuum, \lambda_o=620\ nm

(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.

We know that,

Refractive index,

n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s

(b) The wavelength of light in material,

\lambda=\dfrac{\lambda_o}{n}

Let \lambda_1 is the wavelength of these waves in the liquid. So,

\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m

Hence, this is the required solution.

7 0
3 years ago
A 588 mother sits on one side of a seesaw, 2.20m away from the pivot. one of her two children sits 2.00m from the pivot on the o
erastovalidia [21]
Using momentum balance:

The 588 N mother is on the other side of the seesaw, 2.20m away from the pivot

F1 = 588 N
x1 = 2.20 m

Two of her children sat on the other side:

F2 = 256 N
x2 = 2.00 m

F3 = 412 N
x3 = unknown

F1x1 = F2x2 + F3x3

Solve for x3:

588 * 2.2 = 256 * 2 + 412 * x3

x3 =  1.90 meters away from pivot
3 0
3 years ago
A 1 uF parallel-plate capacitor is charged to 12 V and then disconnected from the voltage supply. The plate separation distance
nlexa [21]

Answer:

22

Explanation:

6 0
3 years ago
Consider a gate whose Shape is a parabolic arch of height 3m and base width 3m. If the origin of the coordinate system is at the
vitfil [10]

Answer:

An arch in a memorial park, having a parabolic shape, has a height of 25 feet and a base width of 30 feet.

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3 years ago
How much work (in J) is required to expand the volume of a pump from 0.0 L to 2.7 L against an external pressure of 1.0 atm?
spin [16.1K]

Answer:

-2.79 x 10²J

Explanation:

using the pressure volume work formula which states that

work = -PΔV

           = -(1.0 atm) (2.7-0.0)L = -2.7L . atm

Convert litre.atmosphere to Joules.

1 L . atm = 101.325 joules

-2.75 L .atm = -2.75 x 101.325 = -278.64375 =

Work = -2.79 x 10²J

5 0
4 years ago
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