Explanation:
It is given that,
Wavelength of a beam of light in vacuum, 
(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.
We know that,
Refractive index,

(b) The wavelength of light in material,

Let
is the wavelength of these waves in the liquid. So,

Hence, this is the required solution.
Using momentum balance:
The 588 N mother is on the other side of the seesaw, 2.20m away from the pivot
F1 = 588 N
x1 = 2.20 m
Two of her children sat on the other side:
F2 = 256 N
x2 = 2.00 m
F3 = 412 N
x3 = unknown
F1x1 = F2x2 + F3x3
Solve for x3:
588 * 2.2 = 256 * 2 + 412 * x3
x3 = 1.90 meters away from pivot
Answer:
An arch in a memorial park, having a parabolic shape, has a height of 25 feet and a base width of 30 feet.
Answer:
-2.79 x 10²J
Explanation:
using the pressure volume work formula which states that
work = -PΔV
= -(1.0 atm) (2.7-0.0)L = -2.7L . atm
Convert litre.atmosphere to Joules.
1 L . atm = 101.325 joules
-2.75 L .atm = -2.75 x 101.325 = -278.64375 =
Work = -2.79 x 10²J