Answer:
The impulse on the ball delivered by the floor is 2.52 kg-m/s.
Explanation:
Given that,
Mass of the ball, m = 0.22 kg
It is dropped from an initial height of 1.80 m. It rebounds back after colliding with the floor to a final height of 1.50 m. Initial velocity and final velocity can be calculated using conservation of energy as :

Final velocity,

As the ball rebounds, v = -5.47 m/s
We need to find the impulse on the ball delivered by the floor. We know that impulse is equal to the change in momentum as follows :

So, the impulse on the ball delivered by the floor is 2.52 kg-m/s.
Yes it will, amplitude has influence on speed.
Answer:

Explanation:
As we know that the force due to propeller when it will push the water backwards is given as

now we know that

so we have



here we know that



now the force is given as


now the acceleration of the ship is given by Newton's II law



Answer:
Water Vapor in the air will evaporate
Explanation:
if im wrong please correct me. But i believe that is the right answer.