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Zanzabum
3 years ago
9

What is the maximum number of electrons in the first electron shell, closest to the nucleus?

Chemistry
2 answers:
djverab [1.8K]3 years ago
7 0

Answer:

I believe the answer is B

Explanation:

Ymorist [56]3 years ago
6 0
The correct answer is B. 2
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What information is need to calculate the percent composition of a compound?
Anestetic [448]

Answer:

Molecular formula

Explanation:

Molecular formula in the first place is required to understand which compound we have. We then should refer to the periodic table and find the molecular weight for each atom. Adding individual molecular weights together would yield the molar mass of a compound.

Then, dividing the total molar mass of a specific atom by the molar mass of a compound and converting into percentage will provide us with the percentage of that specific atom.

E. g., calculate the percent composition of water:

  • molecular formula is H_2O;
  • calculate its molar mass: [tex]M = 2M_H + M_O = 2\cdot 1.00784 g/mol + 16.00 g/mol = 18.016 g/mol;
  • find the percentage of hydrogen: [tex]\omega_H = \frac{2\cdot 1.00784 g/mol}{18.016 g/mol}\cdot 100 \% = 11.19 %;
  • find the percentage of oxygen: [tex]\omega_O = \frac{16.00 g/mol}{18.016 g/mol}\cdot 100 \% = 88.81 %.
8 0
3 years ago
Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of
bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol..[1]

O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol..[2]

NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol..[3]

NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}

2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol

2\times \Delta H^o_{4}=470.3 kJ/mol

\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0
3 years ago
Predict which one of the following compounds would be insoluble in water.
quester [9]
CH4 is insoluble in water 
4 0
3 years ago
Read 2 more answers
What is the mass of 0.23 moles of CF4? *
alisha [4.7K]

error loading answer

4 0
3 years ago
Read 2 more answers
Nitrogen monoxide, NO, reacts with hydrogen, H₂, according to the following equation.
Anvisha [2.4K]

Answer : The rate law for the overall reaction is, Rate=k[NO]^2[H_2]

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

As we are given the mechanism for the reaction :

Step 1 : 2NO+H_2\rightarrow N_2+H_2O_2    (slow)

Step 2 : H_2O_2+H_2\rightarrow 2H_2O     (fast)

Overall reaction : 2NO+2H_2\rightarrow N_2+2H_2O

The rate law expression for overall reaction should be in terms of NO\text{ and }H_2.

As we know that the slow step is the rate determining step. So,

The slow step reaction is,

2NO+H_2\rightarrow N_2+H_2O_2

The expression of rate law for this reaction will be,

Rate=k[NO]^2[H_2]

Hence, the rate law for the overall reaction is, Rate=k[NO]^2[H_2]

8 0
3 years ago
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