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Mashcka [7]
3 years ago
7

Be sure to answer all parts. List the following bonds in order of decreasing ionic character: cesium to fluorine, chlorine to ch

lorine, bromine to chlorine, silicon to carbon. (Enter the two elements of the bond into the appropriate box: CsF, ClCl, BrCl, SiC)
Chemistry
1 answer:
likoan [24]3 years ago
8 0

Answer:

Trend in ionic character of bonds: Cs-F > Si-C > Br-Cl > Cl-Cl    

                                                           (most)                          (least)                    

Explanation:

We know that, percentage ionic character of a bond is proportional to electronegativity difference between two constituting atoms.

                   Atom                                                  Electronegativity

                     Cs                                                              0.7

                      F                                                                4.0

                     Cl                                                                3.0

                     Br                                                               2.8

                      Si                                                                1.8

                     C                                                                 2.5

                Bond                                  Electronegativity difference

               Cs-F                                                                   3.3

               Cl-Cl                                                                   0.0

                Br-Cl                                                                  0.2

                Si-C                                                                    0.7

    So trend in ionic character of bonds:

     Cs-F > Si-C > Br-Cl > Cl-Cl

     (most)                         (least)

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At a festival, spherical balloons with a radius of 170.cm are to be inflated with hot air and released. The air at the festival
MissTica

Answer:

The correct answer is 1.5 balloons.

Explanation:

Based on the given question, the radius of the spherical balloons is 170 cm. Therefore, the volume of each balloon will be,  

= 4/3 × π × (170)³ cm³

= 20.5176 × 10⁶ cm³  

= 20.5176 m³

The density of air at 100 degree C s 0.946 Kg m⁻³

The mass of air in each balloon can be calculated by using the formula,  

Mass = density × volume

Mass = 0.946 Kg m⁻³ × 20.5176 m³

Mass = 19.410 Kg

The heat energy, that is, required to bring the air from 25 degree C to 100 degree C will be,  

= 19.410 × 10³ g × (100 -25) degree C × 1.009 J/g degree C

= 14.68 × 10⁵ J

The concentration of butane given is 1.00 Kg or 1000 g

The molecular weight of butane is 58.12 g per mole

The moles or n can be calculated by using the formula,  

n = mass / mol.wt

n = 1000 g/58.12 g/mol = 17.20 mol

The formation of enthalpy of butane at 25 degree C is 125.7 × 10³ J/mol. The evolution of heat energy that take place at the time of burning 17.20 moles of butane is,  

= 125.7 × 10³ J/mol × 17.20 mol

= 2.16 × 10⁶ J

The number of balloons that can be inflated with hot air is,  

= 2.16 × 10⁶ J / 14.68 × 10⁵ J per each balloon

= 1.5 balloons

Hence, maximum of 1.5 balloons can be inflated.  

7 0
3 years ago
What is the formula of the hydride formed by germanium?
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The atoms combine to form compounds to attain stability in nature. The combination of atoms takes place by sharing of electrons between the atoms or complete transfer of electrons from one atom to another. Generally, atoms combine to complete their octet, that is to possess eight electrons in their outer most shell (noble gas configurations) except hydrogen which can attain stability by two electrons in its outer most shell.

Since germanium has 4 electrons in its outer most shell so it needs 4 more electrons to complete its octet and attains the stability. Hydrogen has 1 electron in its outer most shell and it needs only 1 electron to attain stability so, each germanium will combine with 4 hydrogen atoms and thus forming GeH_4 molecule which is stable in nature.

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3 years ago
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3 0
3 years ago
A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is
Romashka [77]

Answer:

\large \boxed{\text{B.) 2.8 atm}}

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 1520 Torr; T₁ =   27 °C

p₂ = ?;               T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (  27 + 273.15) K = 300.15 K

T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\

(c) Convert the pressure to atmospheres

p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}

7 0
3 years ago
How much heat is absorbed/released when 20.00 g of NH3(g) reacts in the presence of excess O2 (g) to produce NO (g) and H2O (l)
FrozenT [24]

Answer:

a. 342.9 kJ of heat are absorbed.

Explanation:

Calculation of the moles of NH_3 as:-

Mass = 20.00 g

Molar mass of NH_3 = 17.031 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{20.00\ g}{17.031\ g/mol}

Moles= 1.1743\ mol

Given that:- \Delta H=+1168\ kJ

It means that 1 mole of NH_3 undergoes reaction and absorbs 1168\ kJ of heat

So,

1168 mole of NH_3 undergoes reaction and absorbs 1168\times 1168\ kJ of heat

<u>Amount of heat absorbed = + 342.9 KJ</u>

7 0
3 years ago
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