Explanation:
Different atoms absorb and emit specific wavelengths of electromagnetic radiation and nothing in between. These absorption and emission spectra are actually used to identify atoms of elements in a substance. This phenomenon is explained by Bohr's theory of quantized energy levels in an atom – called orbital levels. When an electron 'jumps' from a lower to higher orbital level, it absorbs a specific wavelength of electromagnetic radiation specific to the ‘jump’. Vice versa, when an electron 'jumps' to a lower orbital level is emits an equivalent and specific wavelength of electromagnetic radiation.
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A. Adding iodine
hope this helps
Answer:
0.00011 JK.
The process does NOT violate the second law of thermodynamics
Explanation:
The following parameters are given which are going to help in solving for the change in entropy of the system. The term "entropy'' simply means the degree of disorderliness of a system.
=> The temperature of container A = 305 K, the temperature of container B = 295 K and the amount of heat generated when the containers are placed in contact with each other = 1. 1 J.
The change in entropy of the hot container = -(1/305) = - 0.00328 J/K.
The change in entropy of the cold container = 1/295 = 0.00339 J/K.
Therefore, the change in the entropy of the system = - 0.00328 J/K + 0.00339 J/K = 0.00011 JK.
Note that the change in entropy of the system gives a positive value. Hence, this process does not violate the second law of thermodynamics.
The process does NOT violate the second law of thermodynamics.
It’s a or b i think it’s b
Excess reactant : Na
NaCl produced : = 16.497 g
<h3>Further explanation</h3>
Given
Reaction(balanced)
2Na + Cl₂⇒ 2NaCl
20 g Na
10 g Cl₂
Required
Excess reactant
NaCl produced
Solution
mol Na(Ar = 23 g/mol) :
= 20 : 23 = 0.87
mol Cl₂(MW=71 g/mol):
= 10 : 71 g/mol = 0.141
mol : coefficient :
Na = 0.87 : 2 = 0.435
Cl₂ = 0.141 : 1 = 0.141
Limiting reactant : Cl₂(smaller ratio)
Excess reactant : Na
Mol NaCl based on mol Cl₂, so mol NaCl :
= 2/1 x mol Cl₂
= 2/1 x 0.141
= 0.282
Mass NaCl :
= 0.282 x 58.5 g/mol
= 16.497 g
