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arsen [322]
3 years ago
9

Please help me with this question

Chemistry
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

Moon

Explanation:

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which half reaction describe what is taking place at the cathode during the electrolysis of melting salt of NaCl?
Mice21 [21]

Answer:

Na+ e- - Na

Explanation:

8 0
4 years ago
Identify the effect of increasing acidity on the solubility of the given compounds.
Ilia_Sergeevich [38]

All the given compounds are basic on acidifying their solubility increases.

<u>Explanation:</u>

  • C a_{3}\left(P O_{4}\right)_{2} solubility will increase, since it is basic in nature, on acidifying  solubility increases.
  • F e S being basic on acidification, the solubility increases.
  • M g C O_{3} is alkaline in nature, it gets neutralized and there is no increase in acidity.
  • M g B r_{2} is a salt and it shows no effect on acidification.
  • A g I is a salt but insoluble in water and shows no effect on acidification.
  • M g(O H)_{2} is strongly basic in nature, on acidifying the solubility increases.
4 0
4 years ago
How is it possible for carbon to move through the biotic parts of carbon cycle
andrey2020 [161]

Answer:

Explanation:

Through food chains, the carbon that is in plants moves to the animals that eat them. Animals that eat other animals get the carbon from their food too. Carbon moves from plants and animals to soils. When plants and animals die, their bodies, wood and leaves decays bringing the carbon into the ground.

8 0
3 years ago
A = 10 m/s - 5 m/s<br> 5S
sergiy2304 [10]

Answer:

what is the formula?

Explanation:

8 0
3 years ago
`Suppose you have a sample of NaOH (0.0315 L, to be exact). If this amount of NaOH is used to exactly titrate 0.0250 L of HCl th
yuradex [85]

Answer:

0.0835 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

0.0250 L of 0.105 M HCl react.

0.0250 L × 0.105 mol/L = 2.63 × 10⁻³ mol

Step 3: Calculate the reacting moles of NaOH

The molar ratio of NaOH to HCl is 1:1. The reacting moles of NaOH are 1/1 × 2.63 × 10⁻³ mol = 2.63 × 10⁻³ mol.

Step 4: Calculate the molarity of NaOH

2.63 × 10⁻³ moles of NaOH are in 0.0315 L of solution.

M = 2.63 × 10⁻³ mol / 0.0315 L = 0.0835 M

7 0
3 years ago
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