Answer:
It's the bottom layer.
Explanation:
Scientists use the Law of Superposition to determine the relative age of a layer of sedimentary rock:
The oldest rock layer is at the bottom of an undisturbed bed.
Thus, Layer A in the figure below was deposited first.
Answer:

Explanation:
Hello,
In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

So we solve for
by firstly computing the initial pressure:


Finally, we can compute the work by using the following formula:

Best regards.
Answer:
<em>It is known by almost everyone Earth is divided into longitudes and latitudes which are imaginary lines that cut Earth into 2 equal parts.</em>
Explanation:
The main use of dividing Earth into so many imaginary lines is to know no of places perfect location in numbers. Direction and tell tales can make the place talked about a bit confusing but the exact longitudes and latitudes known pill and someone in exact position.
So in the positions given the question 27 ° and 19 ° show the distance of longitude from Prime Meridian While 18 ° and two degrees show the distance from the equator.
Answer:
The Aluminium electron configuration will be 1s^22s^22p^63s^23p^1. The configuration notation provides an easy way for scientists to write and communicate how electrons are arranged around the nucleus of an atom. This makes it easier to understand and predict how atoms will interact to form chemical bonds.
Answer:
Mass = 28.08
Explanation:
Given data:
Mass of Al₂O₃ = 21.8 g
Mass of water = 9.7 g
Mass of Al(OH)₃ = ?
Solution:
Chemical equation:
2Al(OH)₃ → Al₂O₃ + 3H₂O
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 9.7 g/ 18 g/mol
Number of moles = 0.54 mol
Number of moles of Al₂O₃:
Number of moles = mass/molar mass
Number of moles = 21.8 g/ 101.96 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of Al(OH)₃ with Al₂O₃ and H₂O.
Al₂O₃ : Al(OH)₃
1 : 2
0.21 : 2×0.21 = 0.42 mol
H₂O : Al(OH)₃
3 ; 2
0.54 : 2/3×0.54 = 0.36 mol
Mass of Al(OH)₃:
Mass = number of moles × molar mass
Mass = 0.36 mol × 78 g/mol
Mass = 28.08 g