It would have twice as much potential energy.
Answer :
The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².
Explanation :
Given that,
Mass of block = 3.50
Angle = 30°
Force = 15.0 N
Coefficient of kinetic friction = 0.250
We need to calculate the frictional force
Using formula of frictional force
![F_{k}=\mu N](https://tex.z-dn.net/?f=F_%7Bk%7D%3D%5Cmu%20N)
![F_{k}=\mu (F\sin\theta+mg)](https://tex.z-dn.net/?f=F_%7Bk%7D%3D%5Cmu%20%28F%5Csin%5Ctheta%2Bmg%29)
![F_{k}=0.250\times(15\times\sin30^{\circ}+3.50\times9.8)](https://tex.z-dn.net/?f=F_%7Bk%7D%3D0.250%5Ctimes%2815%5Ctimes%5Csin30%5E%7B%5Ccirc%7D%2B3.50%5Ctimes9.8%29)
![F_{k}=0.250\times41.8](https://tex.z-dn.net/?f=F_%7Bk%7D%3D0.250%5Ctimes41.8)
![F_{k}=10.45\ N](https://tex.z-dn.net/?f=F_%7Bk%7D%3D10.45%5C%20N)
(II). We need to calculate the block's acceleration
Using newton's second law of motion
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
![a=\dfrac{F}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BF%7D%7Bm%7D)
![a=\dfrac{F\cos\theta-F_{k}}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BF%5Ccos%5Ctheta-F_%7Bk%7D%7D%7Bm%7D)
![a=\dfrac{15.0\cos30^{\circ}-10.45}{3.50}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B15.0%5Ccos30%5E%7B%5Ccirc%7D-10.45%7D%7B3.50%7D)
![a=0.73\ m/s^2](https://tex.z-dn.net/?f=a%3D0.73%5C%20m%2Fs%5E2)
Hence, The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².
Answer:
B. Air
Explanation:
I'm taking the exam rn ^^
<span>3.78 m
Ignoring resistance, the ball will travel upwards until it's velocity is 0 m/s. So we'll first calculate how many seconds that takes.
7.2 m/s / 9.81 m/s^2 = 0.77945 s
The distance traveled is given by the formula d = 1/2 AT^2, so substitute the known value for A and T, giving
d = 1/2 A T^2
d = 1/2 9.81 m/s^2 (0.77945 s)^2
d = 4.905 m/s^2 0.607542 s^2
d = 2.979995 m
So the volleyball will travel 2.979995 meters straight up from the point upon which it was launched. So we need to add the 0.80 meters initial height.
d = 2.979995 m + 0.8 m = 3.779995 m
Rounding to 2 decimal places gives us 3.78 m</span>
Blood
I learned this in anatomy, and I've taken it twice