1.Which of the following is the best description of the process shown in the image below?

Which area on the line has both some kinetic energy and some gravitational energy?

Yakvenalex [24]

I believe it is either A or B

4 0

3 years ago

Two violinists are trying to play in tune. However, whenever they play their A string at the same time they hear a beat frequenc

kaheart [24]

Answer:

The possible frequencies for the A string of the other violinist is 457 Hz and 467 Hz.

(3) and (4) is correct option.

Explanation:

Given that,

Beat frequency f = 5.0 Hz

Frequency f'= 462 Hz

We need to calculate the possible frequencies for the A string of the other violinist

Using formula of frequency

$f'=f_{1}-f$ ...(I)

$f'=f_{1}+f$ ...(II)

Where, f= beat frequency

f₁ = frequency

Put the value in both equations

$f'=462-5=457\ Hz$

$f'=462+5=467\ Hz$

Hence, The possible frequencies for the A string of the other violinist is 467 Hz and 457 Hz.

4 0

3 years ago

(a) A standard sheet of paper measures 8 1/2 by 13 inches. Find the area of one such sheet of paper in m2.8.5(!meter/39.37in) —

Sergeu [11.5K]

Answer:

a) A = 0.07129 m²

b) A / A ’= 1.77

Explanation:

In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.

width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)

a = 0.2159 m

length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)

l = 0.3302 m

The area of a rectangle is

A = l a

A = 0.3302 0.2159

A = 0.07129 m²

b) we have a second sheet with reduced dimensions

a ’= 3/4 a

l ’= ¾ l

Let's find the area of this glossy sheet

A ’= l’ a ’

A ’= ¾ l ¾ a

A ’= 9/16 l a

To find the factor we divide the two quantities

A / A ’= l a 16 / (9 l a

A / A ’= 1.77

8 0

3 years ago

A ship leaves a port at noon and travels due west at 20 knots. At 6 PM, a second ship leaves the same port and travels northwest

Amanda [17]

Answer:

$v = 12.44 Knots$

Explanation:

First ship starts at Noon with speed 20 Knots towards West

now we know that 2nd ship starts at 6 PM with speed 15 Knots towards North West

so after time "t" of 2nd ship motion the two ships positions are given as

$r_1 = 20(t + 6)\hat i$

$r_2 = 15(t)(cos45\hat i + sin45\hat j)$

now we can find the distance between two ships as

$x = \sqrt{(20(t + 6) - 10.6 t)^2 + (10.6t)^2}$

now we have

$x^2 = (120 + 9.4 t)^2 + (10.6 t)^2$

$x^2 = 200.72 t^2 + 14400 + 2256 t$

now we will differentiate it with respect to time

$2x\frac{dx}{dt} = 401.44 t + 2256$

here we know that

$t = \frac{90}{15} = 6 hours$

so we have

$x = 187.5$

now we have

$2(187.5) v = 401.44(6) + 2256$

$v = 12.44 Knots$

5 0

3 years ago

Why is the sun renewable but oil is non renewable?

DochEvi [55]

Because once you use oil you can not reuse it but the sun you can because it is always here and it has solar energy

4 0

3 years ago