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aev [14]
3 years ago
14

One component of a magnetic field has a magnitude of 0.0404 T and points along the x axis while the other component has a magnit

ude of 0.0739 T and points along the y axis A particle carrying a charge of 2.80 10 5 C is moving along the z axis at a speed of 4.46 103 m s a Find the magnitude of the net magnetic force that acts on the particle b Determine the angle that the net force makes with respect to the x axis
Physics
1 answer:
andrey2020 [161]3 years ago
5 0

Answer:

as we find the resultant of the magnetic field we get in the xy plane. Just perpendicular to this plane i.e. along z-axis the charge is moving. Hence the force acting on the charge will also be in the xy plane.  

Net field = ./(0.078^2 +0.070^2) = 0.105 T  

Angle with x axis is arc tan 0.070/0.072 = 44.2 deg  

So the force acting on the moving charge is got by Bqv  

0.105*5.5*10^-5 * 6*10^3 = 0.03465 N  

So the angle inclined by this force with x axis will be 90+44.2 = 134.2

Explanation:

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Position vs Time
Annette [7]

Answer:

Determining the Slope on a p-t Graph. It was learned earlier in Lesson 3 that the slope of the line on a position versus time graph is equal to the velocity of the object. If the object is moving with a velocity of +4 m/s, then the slope of the line will be +4 m/s

7 0
3 years ago
A stone is thrown vertically upward with a speed of 12m/s from the edge of a cliff 70 m high (a) How much later it reaches the b
jonny [76]

Answer

given,

vertical speed of stone,v = 12 m/s

height of the cliff = 70 m

a) time taken by the stone to reach at the bottom of the cliff

We know that,

S = u t + 1/2 a t²

- 70 = 12 t - 0.5 x 9.8 t²

4.9 t² - 12 t - 70 = 0  

solving the equation

t = 5.2 s (neglecting the negative value)

b) again using equation of motion

   v = u + a t

   v = 12 - 9.8 x 5.2

  v = -38.96 m/s

ignoring the negative sign

magnitude of velocity is equal to 38.96 m/s

c) total distance travel by the stone

  vertical distance covered by the stone

 v² = u² + 2 g h

 0 = 12² - 2 x 9.8 x h

 h = 7.34 m

to reach the stone to the same level distance travel be doubled.

Total distance travel by the stone

H = h + h + 70

H = 7.34 x 2 + 70

H = 84.7 m.

8 0
3 years ago
A woman 5.5 ft walks at a rate of 6 ft/sec towards a street light that is 22 ft above the ground. At what rate is the length of
Soloha48 [4]

Answer:

The length of her shadow is changing at the rate  -2 m/s

Explanation:

Let the height oh the street light, h = 22 ft

Let the height of the woman, w = 5.5 ft

Horizontal distance to the street light = l

length of shadow = x

h/w = (l + x)/x

22/5.5 =  (l + x)/x

4x = l + x

3x = l

x = 1/3 l

taking the derivative with respect to t of both sides

dx/dt = 1/3 dl/dt

dl/dt = -6 ft/sec ( since the woman is walking towards the street light, the value of l is decreasing with time)

dx/dt = 1/3 * (-6)

dx/dt = -2 m/s

7 0
3 years ago
Read 2 more answers
Científico que formuló 3 leyes de astronomía
s2008m [1.1K]

Answer:

El astrónomo alemán Johannes Kepler

Explanation:

Primera Ley:

Los planetas giran alrededor del Sol siguiendo una trayectoria elíptica. El Sol se sitúa en uno de los focos de la elipse.

La excentricidad e de una elipse es una medida de lo alejado que se encuentran los focos del centro.

Pues bien, la mayoría de las órbitas planetarias tienen un valor muy pequeño de excentricidad, es decir e ≈ 0. Esto significa que, a nivel práctico, pueden considerarse círculos descentrados.

Segunda Ley:

La recta que une el planeta con el Sol barre áreas iguales en tiempos iguales.Para que esto se cumpla, la velocidad del planeta debe aumentar a medida que se acerque al Sol. Esto sugiere la presencia de una fuerza que permite al Sol atraer los planetas, tal y como descubrió Newton años más tarde.

Tercera ley de Kepler:

La tercera ley, también conocida como armónica o de los periodos, relaciona los periodos de los planetas, es decir, lo que tardan en completar una vuelta alrededor del Sol, con sus radios medios.

Para un planeta dado, el cuadrado de su periodo orbital es proporcional al cubo de su distancia media al Sol.

4 0
3 years ago
If the real gi tract is 9 meters long, the model you created is what fraction of the real one
Sedbober [7]

Answer:

a

Explanation:

a

7 0
4 years ago
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