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Answer:
1.6 grams
Explanation:
We need to prepare 100 mL (0.100 L) of a 0.10 M CuSO₄ solution. The required moles of CuSO₄ are:
0.100 L × 0.10 mol/L = 0.010 mol
The molar mass of CuSO₄ is 159.61 g/mol. The mass corresponding to 0.010 moles is:
0.010 mol × (159.61 g/mol) = 1.6 g
We should use 1.6 grams of CuSO₄.
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For what? what is your question
The name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.
<h3>Nomenclature of Organic compounds</h3>
From the question, we are to determine the name of the given molecule.
To name the compound, we will follow the IUPAC rules.
Some of IUPAC rules are
- Find the longest continuous carbon chain. Determine the root name for this parent chain.
- For Alkenes (organic compounds with double bond), number the chain of carbons that includes the C=C so that the C=C has the lower position number. Change “ane” to “ene” and assign a position number to the first carbon of the C=C.
The given compound has 8 carbons and a double bond. The root name of the compound is octane.
By <u>IUPAC rules</u>, the compound is an <u>Octene</u>.
Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.
Hence, the name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.
Learn more on Nomenclature of Organic compounds here: brainly.com/question/26754333
The diagram for the compound is attached below.