Answer:
The statement that describes the advantage of a nonrenewable energy source is that ' they are currently found in abundance' Option D.
Explanation:
Nonrenewable energy sources are sources of energy which will not be replenished after their use, their production usually takes millions of years to be accomplished, Like crude oil, the synthesis under the ground was believed to take Millenium from the various geothermic reactions that occur on the buried biomass millions of years ago.
However, since these energy sources are liable to be exhausted quickly due to their unreplenish nature, nature provides them in abundance. They are currently found in large quantity. Take for example, the coal deposit and crude oil wells which had been mined for many years before now. The continuous usage of these nonrenewable sources nevertheless makes them to be susceptible to exhaustion in some years to come.
The ore contains 55.4% calcium phosphate (related to the mineral apatite) so the amount of Ca3(PO4)2 is 55.4%x=1000g so x=1000/0.554= 1.805kg. Now for the % of P in this amount of calcium phosphate, use all the masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95 (NB oxygen is 16 mass x 4 =64) so the total mass is 310.2 and we have 61.95 of P (Pmass x 2) so 61.95/3102.= 0.19 or 19% P. So of the 1.805 x 0.19= 0.34kg of phosphorus.
Answer:
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Answer:
5.31x10⁻⁶ C
Explanation:
The cube is located 100 m altitude from the ground, so the superior face is at 100m and has E = 70 N/C, and the inferior face is at the ground with E = 130 N/C.
The electric field is perpendicular to the bottom and the top of the cube, so the total flux is the flux at the superior face plus the flux at the inferior face:
Фtotal = Ф100m + Фground
Where Ф = E*A*cos(α). α is the angle between the area vector and the field (180° at the topo and 0° at the bottom):
Фtotal = E100*A*cos(180°) + Eground*A*cos(0°)
Фtotal = 70A*(-1) + 130*A*1
Фtotal = 60A
By Gauss' Law, the flux is:
Фtotal = q/ε, where q is the charge, and ε is the permittivity constant in vacuum = 8.854x10⁻¹² C²/N.m²
A = 100mx100m = 10000 m²
q = 60*10000*8.854x10⁻¹²
q = 5.31x10⁻⁶ C
3 answer for number 3.4 is the answer for number 4
