The accepted length of a steel pipe is 6.7 m. Calculate the percent error of each of these measurements.

Chemistry

1 answer:

disa [49]3 years ago

4 0

Answer:

a. 1.49%

b. -8.95%

c. 0%

d. -1.49%

Explanation:

a. Actual length = 6.7 m

Measured length = 6.8 m

% error = (Measured length - Actual Length)/Actual Length * 100

= (6.8-6.7)/6.7 * 100 = 0.1/6.7 * 100 = 1.49%

b. Actual length = 6.7 m

Measured length = 6.1 m

% error = (Measured length - Actual Length)/Actual Length * 100

= (6.1-6.7)/6.7 * 100 = -0.6/6.7 * 100 = -8.95%

c. Actual length = 6.7 m

Measured length = 6.7 m

% error = (Measured length - Actual Length)/Actual Length * 100

= (6.7-6.7)/6.7 * 100 = 0.1/6.7 * 100 = 0%

a. Actual length = 6.7 m

Measured length = 6.6 m

% error = (Measured length - Actual Length)/Actual Length * 100

= (6.6-6.7)/6.7 * 100 = -0.1/6.7 * 100 = -1.49%

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An osmolarity of saline solution is 308 mosmol/L.

m(NaCl) = 9 g; the mass of sodium chloride

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