Construct a multistep synthetic route from ethylbenzene to (2-bromoethyl)benzene by dragging the appropriate items into the bins
. Note that each bin will hold only one item, and not all reagents and structures will be used.
1 answer:
Answer:
(1)NBS, ROOR (2) and (3)HBr, ROOR
Explanation:
Conversion of ethylbenzene to (2-bromoethyl)benzene involves three steps.
First step: allylic bromination of ethylbenzene in presence of NBS, ROOR. This step produces (1-bromoethyl)benzene.
Second step: E2 ellimination of HBr from (1-bromoethyl)benzene in presence of a strong base e.g. potassium t-butoxide []. This step produces styrene
Third step: HBr addition to double bond in presence of HBr, ROOR (antimarkonikov addition of HBr). Thus step produces (2-bromoethyl)benzene.
Full reaction scheme has been shown below.
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Answer: Rate in terms of disappearance of =
Rate in terms of disappearance of =
Rate in terms of appearance of =
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate in terms of disappearance of =
Rate in terms of disappearance of =
Rate in terms of appearance of =