Answer:
The solution becomes colorless and a light blue precipitate is formed.
Explanation:
When sodium hydroxide is added to copper(II) nitrate solution, a precipitate of copper(II) hydroxide is formed.
The solution gradually becomes colorless as the light blue precipitate appears.
The reaction is complete (enough sodium hydroxide has been added) when the blue color of the solution completely disappears.
The equation of the reaction is;
Cu(NO3)2(aq) + 2NaOH(aq) → Cu(OH)2(s) + 2NaNO3(aq)
Answer:

Explanation:
From the equation attached ,
is reduced. This is because reduction is equivalent to decrease in the oxidation number. In the equation , The oxidation number of Ni is reduced from +2 to 0.
NB, The oxidation number of a neutral atom is zero
What exactly is this asking
Iron phosphate when in acidic solution would dissociate into ions namely the iron ions and the phosphate ions. Furthermore, the phosphate ion would react to the hydronium ions forming HPO4^2-. To determine the net ionic equation we do as follows:
FePO4 <---------> Fe3+ + (PO4)3-
(PO4)3- + H3O+ <--------------> HPO4^2- + H2O
Adding the two equations would yield to:
FePO4(s) + H3O+(aq) ⇌ Fe^3+(aq) + HPO4^2−(aq) + H2O(l)