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Gwar [14]
3 years ago
13

Discussion: (24 points)

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
6 0
What exactly is this asking
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The kw for water at 0 °c is 0.12× 10–14 m2. Calculate the ph of a neutral aqueous solution at 0 °c.
jekas [21]

Answer:

pH = 7.46.

Explanation:

  • The ionization of water is given by the equation :

<em>H₂O(l) ⇄ H⁺(aq) + OH⁻(aq),</em>

<em></em>

  • The equilibrium constant (Kw) expression is:

<em>Kw = [H⁺][OH⁻] = 0.12 x 10⁻¹⁴.  </em>

<em></em>

in pure water and neutral aqueous solution, [H⁺] = [OH⁻]  

So, Kw = [H⁺]²

∴ 0.12 x 10⁻¹⁴ = [H⁺]²

∴ [H⁺] = 3.4 x 10⁻⁸ M.

∵ pH = - log [H⁺]  

pH = - log (3.4 x 10⁻⁸) = 7.46.

8 0
3 years ago
An isotope with a half life of 10 min and a starting sample size of 100 g would have
IgorC [24]

Answer:

12.5 gm left

Explanation:

30 minutes is THREE half lives

   1/2^3 = 1/8th   would be left

100g * 1/8 = 12.5 gm

7 0
2 years ago
In this image, which fundamental interaction is responsible for attracting the electron?
Elza [17]

Answer:

a.

Explanation:

electromagnetism

8 0
3 years ago
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Draw the product or products that are obtained from the reaction of HCl with 1-butene and with 2-butene. Show the relative stere
Bezzdna [24]

Delete me please!!!!!!

8 0
3 years ago
What are twoparts of an atom
Leto [7]
The answer is neutrons and protons.

Hope you got it!!
6 0
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