Question

Kp for the reaction CO2(g) + C(s) --- 2CO(g) is 1.47 at 727°C. Calculate Kc at this temperature.

Answer 1

Answer:

The correct answer is "0.0179".

Explanation:

The given reaction is:

⇒ $CO_2(g) + C(s) \rightleftharpoons 2 \ CO(g)$

The given value is:

At 727°C temperature,

Kp = 1.47

As we know,

Gas constant,

R = 0.0821 L atm/mol.K

Temperature,

= $727+273$

= $1000 \ K$

Now,

The change in moles will be:

⇒ $\Delta n=Products-reactants$

⇒       $=2-1$

⇒       $=1$

As we know,

⇒  $K_p=K_c(RT)^{\Delta n}$

On substituting the given values, we get

⇒  $1.47=K_c(0.0821\times 1000)^1$

⇒    $K_c=\frac{1.47}{0.0821\times 1000}$

⇒          $=\frac{1.47}{82.1}$

⇒          $=0.0179$