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Zina [86]
3 years ago
11

Compared to a 1-kg block of solid iron, a 2-kg block of solid iron has twice as much

Physics
1 answer:
Tcecarenko [31]3 years ago
3 0

Answer:

D. All of the above.

Explanation:

Iron has a constant density, which means 2-kg block will have twice as much volume as 1-kg block; therefore, choice A is correct.

Inertia is defined by the equation F = ma: it measures how hard it is to change the motion of an object. The inertia of the the 1-kg solid iron is

F = 1a,

And the inertia of the 2-kg solid iron is

F = 2a,

which is twice as much that of the 1-kg block; therefore, choice B is correct.

The mass of the 2-kg block is twice as much as that of the 1-kg block; therefore, choice C is also correct.

Thus, all of the choices are correct (D).

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eimsori [14]
Using Newton's second law;

F = ma, where m = mass, a = acceleration or deceleration

a = Δv/t = (v-u)/t, but v= 0, u = 10 m/s, t = 1.
Then,
a = (0-10)1 = -10 m/s^2

Substituting;
F = ma = 10*-10 = -100 N

The  mattress exerts 100 N to stop the ball.
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Hanna tosses a ball straight up with enough speed to remain in the air for several seconds?
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A) the velocity is 0 m/s
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What is the momentum of a bird with a mass of 0.018kg flying at 15m/s?
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Answer:

0.27 kg-m/s

Explanation:

i believe this is the correct answer

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What body systems help these cells get the energy they need?
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The body systems that help cells get the energy they need are the digestive system and circulatory system. The first system is the digestive system because when you eat food, your body breaks it down using the stomach and other different parts of the digestive system.  The next one is the circulatory system because your blood carries the nutrients you acquired from food you digested to the cells throughout your body.

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3 years ago
What are (a) the energy of a photon corresponding to wavelength 6.0 nm, (b) the kinetic energy of an electron with de Broglie wa
dlinn [17]

Explanation:

Given that,

Wavelength = 6.0 nm

de Broglie wavelength = 6.0 nm

(a). We need to calculate the energy of photon

Using formula of energy

E = \dfrac{hc}{\lambda}

E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-9}}

E=3.315\times10^{-17}\ J

(b).  We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

\lambda=\dfrac{h}{\sqrt{2mE}}

E=\dfrac{h^2}{2m\lambda^2}

Put the value into the formula

E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-9})^2}

E=6.709\times10^{-21}\ J

(c). We need to calculate the energy of photon

Using formula of energy

E = \dfrac{hc}{\lambda}

E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-15}}

E=3.315\times10^{-11}\ J

(d). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

\lambda=\dfrac{h}{\sqrt{2mE}}

E=\dfrac{h^2}{2m\lambda^2}

Put the value into the formula

E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-15})^2}

E=6.709\times10^{-9}\ J

Hence, This is the required solution.

6 0
3 years ago
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