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3 years ago

Compared to a 1-kg block of solid iron, a 2-kg block of solid iron has twice as much

Physics

1 answer:

Tcecarenko [31]3 years ago

3 0

Answer:

D. All of the above.

Explanation:

Iron has a constant density, which means 2-kg block will have twice as much volume as 1-kg block; therefore, choice A is correct.

Inertia is defined by the equation F = ma: it measures how hard it is to change the motion of an object. The inertia of the the 1-kg solid iron is

F = 1a,

And the inertia of the 2-kg solid iron is

F = 2a,

which is twice as much that of the 1-kg block; therefore, choice B is correct.

The mass of the 2-kg block is twice as much as that of the 1-kg block; therefore, choice C is also correct.

Thus, all of the choices are correct (D).

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The electric field strength in the space between two closely spaced parallel disks is 1.0 10^5 N/C. This field is the result of

alex41 [277]

To solve this problem it is necessary to apply the concepts related to the capacitance in the disks, the difference of the potential and the load in the disc.

The capacitance can be expressed in terms of the Area, the permeability constant and the diameter:

$C = \frac{\epsilon_0 A}{d}$

Where,

$\epsilon_0$ = Permeability constant

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d = Diameter

Potential difference between the two disks,

V = Ed

Where,

E = Electric field

d = diameter

Q = Charge on the disk equal to $\rightarrow Q=ne=(3.9*10^9)(1.6*10^{-19})= 6.24*10^{-10}C$

Through the value found and the expression given for capacitance and potential, we can define the electric charge as

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$Q = \frac{\epsilon A}{d}(Ed)$

$Q = \epsilon_0 AE$

$Q = \epsilon_0 \pi(\frac{d}{2})^2E$

$Q = \frac{\epsilon \pi d^2E}{4}$

Re-arranging the equation to find the diameter of the disks, the equation will be:

$d = \sqrt{\frac{4D}{\epsilon_0 \pi E}}$

Replacing,

$d = \sqrt{\frac{4(6.24*10^{-10})}{(8.85*10^{-12})\pi(1*10^{5})}}$

$d = 0.0299m$

Therefore the diameter of the disks is 0.03m

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DaniilM [7]

Answer: That's air resistance.

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