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2 years ago

Rasheed ran down the football field at a speed of 7m/s. If he got to the end in 23

Physics

1 answer:

stira [4]2 years ago

7 0

Answer:

<h3>The answer is 161 m</h3>

Explanation:

To find the distance covered we use the formula

<h3>distance = velocity × time</h3>

From the question

velocity = 7 m/s

time = 23 s

We have

distance = 7 × 23

We have the final answer as

Hope this helps you

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(HELP!! 10pts) a train travels 75km in 1hr, and then 68km in 2hrs. what is its average speed?

blondinia [14]

Average speed = total distance travelled ÷ total time taken

AS = (75km + 68km) ÷ (1hr + 2hr)

As = 143km ÷ 3hr

AS = 47.66667 km/hr

AS = 47.7 km/hr (3sf)

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2 years ago

How do you comprehend the fourth dimension?

sergij07 [2.7K]

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2 years ago

Constant Acceleration Kinematics: Car A is traveling at 22.0 m/s and car B at 29.0 m/s. Car A is 300 m behind car B when the dri

Ainat [17]

Answer:

The taken is $t_A = 19.0 \ s$

Explanation:

Frm the question we are told that

The speed of car A is $v_A = 22 \ m/s$

The speed of car B is $v_B = 29.0 \ m/s$

The distance of car B from A is $d = 300 \ m$

The acceleration of car A is $a_A = 2.40 \ m/s^2$

For A to overtake B

The distance traveled by car B = The distance traveled by car A - 300m

Now the this distance traveled by car B before it is overtaken by A is

$d = v_B * t_A$

Where $t_B$ is the time taken by car B

Now this can also be represented as using equation of motion as

$d = v_A t_A + \frac{1}{2}a_A t_A^2 - 300$

Now substituting values

$d = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

Equating the both d

$v_B * t_A = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

substituting values

$29 * t_A = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

$7 t_A = \frac{1}{2} (2.40)^2 t_A^2 - 300$

$7 t_A =1.2 t_A^2 - 300$

$1.2 t_A^2 - 7 t_A - 300 = 0$

Solving this using quadratic formula we have that

$t_A = 19.0 \ s$

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2 years ago

Ana walks from 4 m to 200 cm. Which of the following statements is true about

Gemiola [76]

Distance=2m

because 200cm = 2m
so 4m-2m=2m

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2 years ago

How do you appreciate sweating mechanism of human body to control the temperature of the body?

ehidna [41]

Explanation:

When the body temperature tends to rise, such as during physical exercise, the body begins to sweat. The sweat with high water content is secreted in the skin and when it evaporates into the environment, it cools the body. This is due to the property of water having high heat capacity. It carries with it a lot of heat per molecule (because water requires much energy – than most materials - for its temperature to rise by a degree) hence ideal for cooling. This is why on a hot day, sweating makes the skin feel cooler than the surrounding.

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3 years ago