URGENT! who hypothesized that electrons orbit around a nucleus?

A parallel-plate air capacitor with a capacitance of 260 pF has a charge of magnitude 0.155 Î¼C on each plate. The plates have a

butalik [34]

Answer:

The potential difference between the plates is 596.2 volts.

Explanation:

Given that,

Capacitance $C=260\ pF$

Charge $q=0.155\ \mu\ C$

Separation of plates = 0.313 mm

We need to calculate the potential difference between the plates

Using formula of potential difference

$V= \dfrac{Q}{C}$

Where, Q = charge

C = capacitance

Put the value into the formula

$V=\dfrac{0.155\times10^{-6}}{260\times10^{-12}}$

$V=596.2\ volts$

Hence,The potential difference between the plates is 596.2 volts.

7 0

4 years ago

You pull on a crate with a rope. If the crate moves, the rope's pull on the crate must have been larger than the crate's pull on

GalinKa [24]

Answer:

the affirmation is False

Explanation:

This expression can be analyzed using Newton's laws and specifically Newton's third law that establishes that the force that one body (1) exerts on another body (2) is of the same magnitude as the force exerted by the second body on the first, but in the opposite direction.

Based on this law, the body applies a force to the box and the box reacts with a force on the string of equal magnitude, no matter if it is moving or not, but it contrary direction,

in view of this explanation the affirmation is False

4 0

3 years ago

Determine the magnitude and direction of the resultant velocity of 75.0 m/s. 25.0 east of north, and 100.0 m/s, 25.0 east of sou

aleksandr82 [10.1K]

Answer:

77.35 m / s

Ф = -17° from + X axis or 343° from + X axis

Explanation:

v1 = 75 m/s 25° east of north

v2 = 100 m/s 25° east of south

Write the velocities in vector form ,we get

$\overrightarrow{v_{1}}=75\left ( Sin25\widehat{i} +Cos25\widehat{j}\right )=31.7\widehat{i}+67.97\widehat{j}$

$\overrightarrow{v_{1}}=100\left ( Sin25\widehat{i} -Cos25\widehat{j}\right )=42.26\widehat{i}-90.63\widehat{j}$

Now add the velocity vectors to get the resultant of the velocities.

$\overrightarrow{v}=\overrightarrow{v_{1}}+\overrightarrow{v_{2}}$

$\overrightarrow{v}=\left (31.7+42.26 \right )\widehat{i}+\left ( 67.97- 90.63 \right )\widehat{j}$

$\overrightarrow{v}=73.96\widehat{i}-22.66\widehat{j}$

magnitude of resultant velocity is $\sqrt{\left ( 73.96 \right )^{2}+\left ( -22.66 \right )^{2}}$

= 77.35 m / s

The direction is Ф from X axis

$tan\phi =\frac{-22.66}{73.96}=-0.306$

Ф = -17° from + X axis or 343° from + X axis

7 0

4 years ago

a shot putter accelerates a 7.3kg shot from rest to 14m/s in 1.5r seconds. what average power was developed?

Sedaia [141]

Explanation:

$power = \frac{energy \: expended}{time}$

m = 7.3kg

u = 0

v = 14m/s

t = 1.5sec

P = (0.5×7.3×14²) ÷ 1.5

P = 476.93

P = 477 watt

3 0

4 years ago

You've always wondered about the acceleration of the elevators in the 101-story-tall Empire State Building. One day, while visit

kondor19780726 [428]

Answer:

(i) The maximum acceleration upward is 2.02 m/s².

(ii) The maximum acceleration downward is 1.39 m/s².

Explanation:

Let a be the maximum acceleration of the elevator.

The mass of the person at ground is 150 lb. We have to convert the mass into kg,

1 lb = 0.453592 kg

150 lb = 68 kg

170 lb = 77 kg

120 lb = 54 kg

(i) The person experience a force due to Earth's gravity in the downwards direction. The magnitude of this force is:

F₁ = mg = 68 x 9.8 = 666.4 N

The weight of the person decreases as the elevator is moving upwards. So, the force experienced by the person in this case due to gravity is:

F₂ = 54 x 9.8 = 529.2 N

Applying Newton's force equation;

(F₁ - F₂) = ma

(666.4 - 529.2) = 68 x a

a = 2.02 m/s²

(ii) The weight of the person increases as the elevator is moving downwards. So, the force experienced by the person in this case due to gravity is:

F₂ = 77 x 9.8 = 754.6 N

Applying Newton's force equation;

(F₁ - F₂) = ma

(666.4 - 754.6) = 68 x a

a = -1.30 m/s²

8 0

4 years ago