Answer:
The weight of the landing craft in the vicinity of Callisto's surface is 3480 N.
Explanation:
The engine of the craft provides an upward thrust of so that the space craft descends at a constant speed.
This implies that the net force on the space craft is zero.
The upward thrust will be equal to the downward gravitational pull by Callisto.
So the weight of the craft near the vicinity will be 3480 N.
The centripetal force acting on the ball will be 23.26 N.The direction of the centripetal force is always in the path of the center of the course.
<h3>What is centripetal force?</h3>The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.
The given data in the problem is;
m is the mass of A ball = 0.25 kg
r is the radius of circle= 1.6 m rope
v is the tangential speed = 12.2 m/s
is the centripetal force acting on the ball
The centripetal force is found as;
Hence the centripetal force acting on the ball will be 23.26 N.
To learn more about the centripetal force refer to the link;