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lorasvet [3.4K]
3 years ago
15

What is the percentage increase IN kinetic energy(K.E) ,If the momentum(p) of a moving body is increase by 10%?And How? (If K.E=

p^2/2m)
Physics
1 answer:
DerKrebs [107]3 years ago
5 0
KE =  \frac{p^2}{2m} (start kinetic energy)
KE =  \frac{(1.1p)^2}{2m} =1.21 \times  \frac{p^2}{2m}
KE_n_e_w=1.21\times KE_o_l_d
Therefore increasing the momentum by 10% increases KE by 21%.
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Suppose that a public address system emits sound uniformly in all directions and that there are no reflections . The intensity a
Marina86 [1]

Answer:

I_{2}=2.39*10^{-5} W/m^{2}

Explanation:

The definition of the intensity in terms of power is given by:

I=\frac{P}{A}

Where:

  • P is the power
  • A is the area

If the sound emits uniformly in all directions and that there are no reflections, we can assume the geometry of the wave sound is spherical.

Let's recall the area of a sphere is A = 4\pi R^{2}

To the first location we have:

I_{1}=3*10^{-4} W/m^{2}=\frac{P}{4\pi 22^{2}}

and to the second location we have:

I_{2}=\frac{P}{4\pi 78^{2}}

Now, we can divide each intensity to find the second intensity.

\frac{I_{2}}{I_{1}}=\frac{\frac{P}{4\pi 78^{2}}}{\frac{P}{4\pi 22^{2}}}

I_{2}=I_{1}* \frac{22^{2}}{78^{2}}

I_{2}=3*10^{-4}\frac{22^{2}}{78^{2}}

I_{2}=2.39*10^{-5} W/m^{2}

I hope it helps you!

     

5 0
3 years ago
Read 2 more answers
A Thomson's gazelle can run at very high speeds, but its acceleration is relatively modest. A reasonable model for the sprint of
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Answer:

The gazelles top speed is 27.3 m/s.

Explanation:

Given that,

Acceleration = 4.2 m/s²

Time = 6.5 s

Suppose we need to find the gazelles top speed

The speed is equal to the product of acceleration and time.

We need to calculate the gazelles top speed

Using formula of speed

v=at

Where, v = speed

a = acceleration

t = time

Put the value into the formula

v=4.2\times6.5

v=27.3\ m/s

Hence, The gazelles top speed is 27.3 m/s.

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A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the spe
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Answer: V = 15 m/s

Explanation:

As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

Where

F = observed frequency

f = source frequency

C = speed of light = 3×10^8

V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

300000014.7 - 1.000000049V = 3×10^8

Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

The speed of the car is 15 m/s approximately

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