1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
siniylev [52]
3 years ago
12

! ' 30 !! !

Physics
1 answer:
ELEN [110]3 years ago
7 0

Answer:

Hey

Unlike visible light, X-rays can go through you without getting absorbed. But some of it gets absorbed but most of it passes through, this tiny bit that does get absorbed shows you the image of the baby.

You might be interested in
Lifting a rope A mountain climber is about to haul up a 50-m length of hanging rope. How much work will it take if the rope weig
timama [110]

Answer:

780 J

Explanation:

W=\int _{\:0}^{50}0.624xdx

4 0
2 years ago
On earth, you swing a simple pendulum in simple harmonic motion with a period of 1.6 seconds. what is the period of this same pe
polet [3.4K]
The period of a simple pendulum is given by
T= 2 \pi  \sqrt{ \frac{L}{g} }
where
L is the pendulum length
g is the acceleration of gravity

If we move the same pendulum from Earth to the Moon, its length L remains the same, while the acceleration of gravity g changes. So we can write the period of the pendulum on Earth as:
T_e= 2 \pi \sqrt{ \frac{L}{g_e} }
where g_e is the acceleration of gravity on Earth, while the period of the pendulum on the Moon is
T_m= 2 \pi \sqrt{ \frac{L}{g_m} }
where g_m is the acceleration of gravity on the Moon. 

If we do the ratio of the two periods, we get
\frac{T_m}{T_e} =  \sqrt{ \frac{g_e}{g_m} }
but the gravity acceleration on the Moon is 1/6 of the gravity acceleration on Earth, so we can write g_e = 6 g_m and we can rewrite the previous ratio as
\frac{T_m}{T_e} = \sqrt{ \frac{6 g_m}{g_m} }=  \sqrt{6}

so the period of the pendulum on the Moon is
T_m =  \sqrt{6}  T_e =  \sqrt{6} (1.6 s)=3.9 s
8 0
4 years ago
Which is true of the buoyant force?
victus00 [196]

It acts in the upward direction.

8 0
3 years ago
A jet, sitting on the runway, takes off and accelerates at 8.0 m/s for 16s. How far did the jet travel down the runway?
nydimaria [60]

Answer:

2.4 m/s". 1

Explanation:

A jet with mass m = 8 x 10* kg jet accelerates down the runway for takeoff at 2.4 m/s". 1

8 0
3 years ago
Light travels at 3.0 × 108 m/s in a vacuum and slows to 2.0 × 108 m/s in glass. What is the index of refraction of glass?
Slav-nsk [51]
We are asked to solve for the index of refraction and the formula is n = c/v where "n" represents the index of refraction, "c" represents the speed of light in the vacuum while "v" represents the speed of another medium.
In the problem, we have the given values below:
c = 3 x 10^8 m/s
v = 2 x 10^8 m/s
n =?

Solving for n, we have the solution below:
n = 3x10^8 /  2x10^8
n = 1.5

The answer is 1.5 for the index of refraction.


8 0
3 years ago
Read 2 more answers
Other questions:
  • 2 A kovács a meleg vasat a hideg vízbe teszi. A vas
    15·1 answer
  • The storage method used for radioactive wastes generated from fission nuclear reactors must be designed to last for how long?
    7·2 answers
  • Nya has a cup of hot tea that she lets cool down for several minutes. What effect does cooling have on the tea?
    7·2 answers
  • What is the smallest part of a compound called?
    8·2 answers
  • The length of the adult mosquito is typically between 3.0 mm and 6.0 mm. The smallest known mosquitoes are around 2.5 mm, and th
    13·1 answer
  • How is Aristotles model similar to Ptolemy’s model
    10·2 answers
  • An automobile tire is filled to a pressure of 240.0 kPa early in the morning when the temperature is 15.0C. After the car is dri
    7·1 answer
  • PLEASE HELP ME WITH THIS
    11·1 answer
  • (a) One medium is air, in which the speed of light is 3.00 x 108 m/s. The other
    7·1 answer
  • Joe runs 10 m north, 20 m south, 9m south, and then 15 m north. What is Joe's<br> displacement?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!