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Helga [31]
3 years ago
13

A swan on a lake gets airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.40

m/s to take off and it accelerates from rest at an average rate of 0.380 m/s², how far (in m) will it travel before becoming airborne?
Physics
1 answer:
Veseljchak [2.6K]3 years ago
6 0

Answer:

53.895 m.

Explanation:

Using the equation of motion,

v² = u² + 2as .............. Equation 1

Where v = final velocity of the swan, u = initial velocity of the swan, a = acceleration of the swan, s = distance covered by the swan.

make s the subject of the equation,

s = (v² - u²)/2a----------- Equation 2

Given: v = 6.4 m/s, u = 0 m/s ( from rest)  a = 0.380 m/s².

Substitute into equation 2

s = (6.4²-0²)/(2×0.380)

s = 40.96/0.76

s = 53.895 m.

Hence the swan will travel 53.895 m before becoming airborne.

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