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Helga [31]
4 years ago
13

A swan on a lake gets airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.40

m/s to take off and it accelerates from rest at an average rate of 0.380 m/s², how far (in m) will it travel before becoming airborne?
Physics
1 answer:
Veseljchak [2.6K]4 years ago
6 0

Answer:

53.895 m.

Explanation:

Using the equation of motion,

v² = u² + 2as .............. Equation 1

Where v = final velocity of the swan, u = initial velocity of the swan, a = acceleration of the swan, s = distance covered by the swan.

make s the subject of the equation,

s = (v² - u²)/2a----------- Equation 2

Given: v = 6.4 m/s, u = 0 m/s ( from rest)  a = 0.380 m/s².

Substitute into equation 2

s = (6.4²-0²)/(2×0.380)

s = 40.96/0.76

s = 53.895 m.

Hence the swan will travel 53.895 m before becoming airborne.

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andreev551 [17]

Answer:

Chemical substances in food that have specific functions in your body are called Nutrients. Examples: proteins, fats, carbohydrates, vitamins, and minerals

Explanation:

These chemical substances keep our body healthy.

These chemical substances prevent the premature aging.

They help our body to fight against diseases.

They build the new tissues and cells for growth.

And in short, they help in the growth, development of our body.

4 0
3 years ago
Calculate the force of gravity on the 0.60-kg mass if it were 1.3×107 m above Earth's surface (that is, if it were three Earth r
KIM [24]
The force of gravity between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation

In this problem, the mass of the object is m_1=0.60 kg, while the Earth's mass is m_2=5.97 \cdot 10^{24} kg. Their separation is r=1.3 \cdot 10^7 m, therefore the gravitational force exerted on the object is
F=(6.67 \cdot 10^{-11}m^3 kg^{-1} s^{-2}) \frac{(0.60 kg)(5.97 \cdot 10^{24} kg)}{(1.3 \cdot 10^7 m)^2}=1.4 N
5 0
3 years ago
Please explain in simple terms why a purple flower appears purple when a white light shines on it?
AleksAgata [21]
The white light is made up of all wavelength of electromagnetic spectrum, the spectrum has different colors, When light rays fall on an object, some of the color in the white light will be absorbed by the object while some will be reflected. The color that is reflected by the object is the one that an observe will see. Thus, a purple flower will appear purple because it is reflecting the wavelength that appear as purple 
6 0
3 years ago
how does the electric force between two charged particles change if the distance between them is increased by a factor of 3? a.
Aleksandr [31]

how does the electric force between two charged particles change if the distance between them is increased by a factor of 3?

a. it is reduced by a factor of 3

4 0
3 years ago
A proton and an electron are fixed in space with a separation of 859 nm. Calculate the electric potential at the midpoint betwee
makkiz [27]

Answer:

The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

Explanation:

Electric potential is given as;

V = E*r

where;

E is the electric field strength, = kq/r²

V = ( kq/r²)*r

V = kq/r

k is coulomb's constant = 8.99 X 10⁹ Nm²/C²

q is the charge of the particles = 1.6 X 10⁻¹⁹ C

r is the distance between the particles = 859 nm

At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm

V = (8.99 X 10⁹  * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)

V = 3.349 X 10⁻³ Volts

Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

3 0
3 years ago
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