1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Helga [31]
3 years ago
13

A swan on a lake gets airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.40

m/s to take off and it accelerates from rest at an average rate of 0.380 m/s², how far (in m) will it travel before becoming airborne?
Physics
1 answer:
Veseljchak [2.6K]3 years ago
6 0

Answer:

53.895 m.

Explanation:

Using the equation of motion,

v² = u² + 2as .............. Equation 1

Where v = final velocity of the swan, u = initial velocity of the swan, a = acceleration of the swan, s = distance covered by the swan.

make s the subject of the equation,

s = (v² - u²)/2a----------- Equation 2

Given: v = 6.4 m/s, u = 0 m/s ( from rest)  a = 0.380 m/s².

Substitute into equation 2

s = (6.4²-0²)/(2×0.380)

s = 40.96/0.76

s = 53.895 m.

Hence the swan will travel 53.895 m before becoming airborne.

You might be interested in
A Styrofoam ball has just been shot straight up. Air resistance is not negligible (free body diagram)
timofeeve [1]

In a free body diagram for an object projected upwards;

  • the acceleration due to gravity on the object is always directed downwards.
  • the velocity of the object is always in the direction of the object's motion.

An object projected upwards is subjected to influence of acceleration due to gravity.

As the object accelerates upwards, its velocity decreases until the object reaches maximum height where its velocity becomes zero and as the object descends its velocity increases, which eventually becomes maximum before the object hits the ground.

To construct a free body diagram for this motion, we consider the following;

  • the acceleration due to gravity on the object is always directed downwards
  • the velocity of the object is always in the direction of the object's motion.

<u>For instance:</u>

upward motion for velocity  ↑        downward motion for velocity  ↓

                                              ↑                                                            ↓

                                              ↑                                                            ↓

acceleration due to gravity ↓

                                             ↓

                                             ↓

Learn more here: brainly.com/question/13235430

5 0
3 years ago
At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball
dedylja [7]

Answer:

Magnitude of net force will be 432.758 N  

Explanation:

We have given x component of acceleration a_x=760m/sec^2

And vertical component of acceleration  a_y=770m/sec^2

Mass of the ball m = 0.40 kg

So net acceleration a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2

Now according to second law of motion

Force = mass × acceleration

So F = 0.40×1081.896 = 432.758 N

3 0
3 years ago
A car accelerates from rest at 3.00 m/second squared What is the velocity after 5 secs ? What is the displacement after 5 second
andrey2020 [161]

Explanation:

after 5 seconds, the velocity is (5s)(3m/s²) = 15m/s

The displacement after 5s is

x=vo + (1/2)at²

x = 0 + (1/2)(3m/s²)(5s)(5s)

x= 37.5 m

3 0
3 years ago
Two wheels having the same radius and mass rotate at the same angular velocity ((Figure 1) ). One wheel is made with spokes so n
liubo4ka [24]

Answer:

E. The wheel with spokes has about twice the KE.

See explanation in: https://quizlet.com/100717504/physics-8-mc-flash-cards/

6 0
3 years ago
Read 2 more answers
If an atomic nucleus were the size of a dime how far away might one of its electrons be?
mihalych1998 [28]
The radius of a nucleus of hydrogen is approximately r_{n1}=1\cdot 10^{-15}m, while we can use the Borh radius as the distance of an electron from the nucleus in a hydrogen atom: r_{e1}=5.3 \cdot 10^{-11}m

The radius of a dime is approximately r_{n2} = 9\cdot 10^{-3}m: if we assume that the radius of the nucleus is exactly this value, then we  can find how far is the electron by using the proportion
r_{n1}:r_{e1}=r_{n2}:r_{e2}
from which we find
r_{e2}= \frac{r_{e1} r_{n2}}{r_{n1}}= \frac{(5.3 \cdot 10^{-11}m)(9\cdot 10^{-3}m)}{1 \cdot 10^{-15}m}=477 m

So, if the nucleus had the size of a dime, we would find the electron approximately 500 meters away.
6 0
3 years ago
Other questions:
  • A light spring has a force constant of 70 N/m and is used to pull a 10 kg box on a horizontal frictionless surface. If the box h
    13·1 answer
  • Frank wrote several statements to summarize the relationship between the first and second laws of thermodynamics.
    11·2 answers
  • Q- A body is acted upon by two forces 30N due east and 40N due North. Calculate
    12·1 answer
  • Cardiovascuar exercise involves
    12·1 answer
  • 3 A picture is supported by two vertical strings; if the weighi
    9·1 answer
  • If a vehicle is traveling at constant velocity and then comes to a sudden stop, has it undergone negative acceleration or positi
    6·1 answer
  • Compound name: for C3N6
    15·1 answer
  • ¿Qué es la fuerza de atracción de los cuerpos?
    10·1 answer
  • Explain melting and freezing using the kinetic theory of matter​
    8·2 answers
  • Dos cargas puntuales q1 = −50μC y q2 = +30μC se encuentran
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!