A swan on a lake gets airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.40
1 answer:
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Answer:
1 m
Explanation:
L = 100 m
A = 1 mm^2 = 1 x 10^-6 m^2
Y = 1 x 10^11 N/m^2
F = 1000 N
Let the cable stretch be ΔL.
By the formula of Young's modulus
ΔL = 1 m
Thus, the cable stretches by 1 m.
Answer:
The ratio is KE : TM = 0.75
Explanation:
from the question we are told that
The displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position
Generally the total mechanical energy of the mass is mathematically represented as
Here k is the spring constant , A is the total displacement of the the mass from maximum compression to maximum extension of the spring
Generally this total mechanical energy is mathematically represented as
=>
Here the potential energy of the mass is mathematically represented as
Here x is the displacement of the mass from maximum compression or extension of the spring to equilibrium position and the value is
So
So
=>
=>
So the ratio of is mathematically represented as
=>