Answer:
d. 100.0 J
Explanation:
To solve this problem we must use the theorem of work and energy conservation. This tells us that the mechanical energy in the final state is equal to the mechanical energy in the initial state plus the work done on a body. In this way we come to the following equation:
E₁ + W₁₋₂ = E₂
where:
E₁ = mechanical energy at state 1. [J] (units of Joules)
E₂ = mechanical energy at state 2. [J]
W₁₋₂ = work done from 1 to 2 [J]
We have to remember that mechanical energy is defined as the sum of potential energy plus kinetic energy.
The energy in the initial state is zero, since there is no movement of the hockey puck before imparting force. E₁ = 0.
The Work on the hockey puck is equal to:
W₁₋₂ = 100 [J]
100 = E₂
Since the ice rink is horizontal there is no potential energy, there is only kinetic energy
Ek = 100 [J]
It can be said that the work applied on the hockey puck turns into kinetic energy
Because it’s hard snow that can kill you
Answer:
B. an action-reaction force pair
Answer:
93.125 × 10^(19)
Explanation:
We are told the asteroid has acquired a net negative charge of 149 C.
Thus;
Q = -149 C
charge on electron has a value of:
e = -1.6 × 10^(-19) C
Now, for us to determine the excess electrons on the asteroid, we will just divide the net charge in excess on the asteroid by the charge of a single electron.
Thus;
n = Q/e
n = -149/(-1.6 × 10^(-19))
n = 93.125 × 10^(19)
Thus, it has 93.125 × 10^(19) more electrons than protons
