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SIZIF [17.4K]
3 years ago
15

Find the perimeter of area of rectangle 5 in 7in

Mathematics
1 answer:
scZoUnD [109]3 years ago
3 0
Area of a rectangle is A=l*w so you have 5 and 7 you times that and you get 35 squared inches
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Having trouble with this one can someone teach me how to find the slope in this question. Try to help me learn it aswell. Its in
ASHA 777 [7]
Hi there! The answer is -2.

We can find the slope of a formula by using the following formula:

slope = \frac{change \: of \: y}{change \: of \: x} =\frac{y2 - y1}{x2 - x1}
x2 and y2 don't mean squared, but the x and y coordinate of our second point.

First we need to find two points on the line. Ijn this particular case we have (-3, 3) and (1, -5). Now we can fill in the formula.

slope = \frac{ - 5 - 3}{1 - - 3} = \frac{ - 8}{4} = - 2

Therefore, the third answer is correct.
~ Hope this helps you!
7 0
3 years ago
Lin runs 5 laps around a track in 6 minutes.
Paladinen [302]

Answer:

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Step-by-step explanation:

6/5 is 1.2, so it takes 1.2 minutes to run one lap.

This means 21 x 1.2 = the minutes it takes to run 21 laps around the track.

Therefore it takes 25.2 minutes to run around the track 21 times.

3 0
2 years ago
Which of the following is a solution of x2 + 2x + 4?
ivolga24 [154]
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:

</span>x^2 + 2x + 4= 0.  "Completing the square" seems to be the easiest way to go here:

rewrite   x^2 + 2x + 4  as   x^2 + 2x + 1^2 - 1^2 = -4, or
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or                                            x+1 =i*(plus or minus sqrt(3))

or                                            x = -1 plus or minus i*sqrt(3)

This problem, like any other quadratic equation, has two roots.  Note that the fourth possible answer constitutes one part of the two part solution found above.
3 0
3 years ago
How to do exponents a quicker way!! Please help my brother!
jekas [21]
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3 0
3 years ago
5x + 10y &gt; 40
mel-nik [20]

Answer:

x > -2y + 8

Step-by-step explanation:

7 0
3 years ago
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