Question

In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for at least 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear?

Answer 1

this question is incomplete.here is complete question

In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for at least 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear?

(1) The diameter of the larger gear is twice the diameter of smaller gear.

(2) The smaller gear revolves 600 times per minute.

Answer:

Number of days larger gear last longer than small gear=115.74 days

Explanation:

Given Data

Revolution=6,000,000,000 revolutions

diameter of larger gear is twice diameter of smaller gear

Smaller gear revolves=600 times per minute

Number of days larger gear last longer than small gear=?

Solution

$No:days=\frac{6,000,000,000}{24*60*60}*((1/300)-(1/600))\\ No:days=115.74days$