this question is incomplete.here is complete question
In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for at least 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear?
(1) The diameter of the larger gear is twice the diameter of smaller gear.
(2) The smaller gear revolves 600 times per minute.
Answer:
Number of days larger gear last longer than small gear=115.74 days
Explanation:
Given Data
Revolution=6,000,000,000 revolutions
diameter of larger gear is twice diameter of smaller gear
Smaller gear revolves=600 times per minute
Number of days larger gear last longer than small gear=?
Solution
Answer:
Change in mechanical energy,
Explanation:
It is given that,
Mass of the projectile, m = 12 kg
Speed of the projectile, v = 20 m/s
Maximum height, h = 18 m
Initially, the projectile have only kinetic energy. it is given by :
K = 2400 J
Finally, it have only potential energy. it is given by :
P = mgh
P =2116.8 J
The change in mechanical energy is given by :
So, the change in mechanical energy is 283.2 J. Hence, this is the required solution.
Answer:
1) tensile stress = 76.648 Mpa
2) extension = 0.0215 m
Explanation:
Detailed explanation and calculation is shown in the image below
