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2 years ago

Answer me nowwwwwwww

Physics

2 answers:

qwelly [4]2 years ago

8 0

Answer:

volume

Explanation:

it depends on the volume of the items

hope this helps

tamaranim1 [39]2 years ago

6 0

Answer:mass

Explanation:

gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects.

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An underground cannon launches a cannonball from ground level at a 35 degree angle. the cannonball is shot with an initial veloc

user100 [1]

Answer:

Time = 1.75[s]; Distance traveled = 21.5 [m]; Max height = 15 [m]

Explanation:

First, we have to break down the velocity vector into the X & y components.

$(v_{x})_{0} = 15 * cos( 35)= 12.28[m/s]\\(v_{y})_{0} = 15 * sin( 35)= 8.6[m/s]\\\\$

To find the time t that lasts the ball of cannon in the air we must use the following equation of kinematics, in this equation the value of y is equal to zero because it will be proposed that the ball lands at the same level that was fired.

$y=(v_{y} )_{0}-\frac{1}{2}*g*t^{2} \\where:\\g=9.81[m/s^2]\\t = time[s]\\y=0[m]$

$0=8.6*t-\frac{1}{2}*9.81*t^{2} \\4.905*t^{2}=8.6*t\\ t=1.75[s]$

In order to find the distance traveled horizontally from the cannonball, we must use the speed kinematics equation in the X coordinate.

$x = (v_{x})_{0} *t\\x=12.28*1.75\\x=21.5 [m]$

In order to find the last value, we must bear in mind that when the cannonball reaches the maximum height, the velocity in the component y is equal to zero, and we can find the value of and with the following kinematic equation

$y = (v_{y})_{0} *t+\frac{1}{2} *g*(t)^{2} \\y = 0*t+\frac{1}{2} *9.81*(1.75)^{2}\\ y=15 [m]$

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