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KonstantinChe [14]
3 years ago
14

Suppose that for a data set • there are m points and K clusters, • half the points and clusters are in "more dense" regions, • h

alf the points and clusters are in "less dense" regions, and • the two regions are well-separated from each other. Which of the following should occur to minimize the squared error when finding K clusters: (a) Centroids should be equally distributed between more dense and less dense regions. (b) More centroids should be allocated to the less dense region. (c) More centroids should be allocated to the denser region. Explain:
Engineering
1 answer:
Crank3 years ago
3 0

Answer:

b

Explanation:

The correct answer should be option b that is

b) more centroids should be allocated to the less dense region and more dense region should have less centroids.

reason

When more dense region has more points in a small area a centroids in that area would have very less distance from that point and hence the calculation would be accurate even with less centroids.

For points spread over a large area, many centroids would help in providing less distance to the points and becoming accurate calculations.

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Give three examples of how engineering has made human life better in your opinion.
omeli [17]

Answer:

This is in your opinion. If you truly wish, you may comment on this and tell me that you need something.

Explanation:

3 0
3 years ago
A ____ is either in the pressure reducer or in the downstream side of the system to ensure that the control air pressure does no
Alika [10]

Answer:

A relief valve is either in the pressure reducer or in the downstream side of the system to ensure that the control air pressure does not exceed about 30 psig.

3 0
2 years ago
A bar of 75 mm diameter is reduced to 73mm by a cutting tool while cutting orthogonally. If the mean length of the cut chip is 7
barxatty [35]

Answer:

r=0.31

Ф=18.03°

Explanation:

Given that

Diameter of bar before cutting = 75 mm

Diameter of bar after cutting = 73 mm

Mean diameter of bar d= (75+73)/2=74 mm

Mean length of uncut chip = πd

Mean length of uncut chip = π x 74 =232.45 mm

So cutting ratio r

Cutting\ ratio=\dfrac{Mean\ length\ of cut\ chip}{Mean\ length\ of uncut\ chip}

r=\dfrac{73.5}{232.45}

  r=0.31

So the cutting ratio is 0.31.

As we know that shear angle given as

tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }

Now by putting the values

tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }

tan\phi =\dfrac{0.31cos15 }{1-0.31sin15 }\

  Ф=18.03°

So the shear angle is 18.03°.

4 0
4 years ago
Why is recycling important
bearhunter [10]
Recycling is important because you can save the planet by using the same plastic instead of throwing it away.
4 0
2 years ago
Read 2 more answers
53. The plan of a building is in the form of a rectangle with
schepotkina [342]

Answer: 150m

Explanation:

The following can be depicted from the question:

Dimensions of outer walls = 9.7m × 14.7m.

Thickness of the wall = 0.30 m

Therefore, the plinth area of the building will be:

= (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)

= 10 × 15

= 150m

7 0
3 years ago
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