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WINSTONCH [101]
3 years ago
14

Need help, I will give cake :)) + branliest

Engineering
2 answers:
Dominik [7]3 years ago
6 0
The answer is a. lol!
Talja [164]3 years ago
3 0

Answer:

A

Explanation:

it goes good with it.

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Situation: Peter is designing a new hybrid car that functions on solar power. He is currently working on sketches of his design
givi [52]

Answer:

whats the question?

Explanation:

8 0
2 years ago
A_____ transducer is a device that can convert an electronic controller output signal into a standard pneumatic output. A. pneum
makkiz [27]

Answer:

The correct answer is

option C. current to pneumatic (V/P)

Explanation:

A current to pneumatic controller is  basically used to receive an electronic signal from a controller and converts it further into a standard pneumatic output signal which is further used to operate a positioner or control valve. These devices are reliable, robust and accurate.

Though Voltage and current to pressure transducers are collectively called as electro pneumatic tranducers and the only electronic feature to control output pressure in them is the coil.

6 0
3 years ago
10% A steel beam W18x76 spans 32 feet and is subjected to a Moment of 334 kips-ft. Find the load w on the beam. Determine the de
Lilit [14]

Answer:

w = 10.437 kips

deflection at 1/4 span  20.83\E ft

at mid span = 1.23\E ft

shear stress  7.3629 psi

Explanation:

area of cross section = 18*76

length of span = 32 ft

moment = 334 kips-ft

we know that

moment = load *eccentricity

334 = w * 32

w = 10.437 kips

deflection at 1/4 span

\delta = \frac{wa^2b^2}{3EI}

= \frac{10.4375*8^2 *24^2}{3E \frac{BD^3}{12}}

         =\frac{10.437 *8^2*24^2}{3E \frac{18*16^3}{12}}

         = 20.83\E ft

at mid span

\delta = \frac{wl^3}{48EI}

= \frac{10.43 *32^3}{48 *E*\frac{18*16^3}{12}}

\delta = 1.23\E ft

shear stress

\tau = \frac{w}{A} = \frac{10.43 7*10^3}{18*76} =7.3629 psi

6 0
3 years ago
Find the percent change in cutting speed required to give an 80% reduction in tool life when the value of n is 0.12.
vaieri [72.5K]

Answer:21.3%

Explanation:

Given

80 % reduction in tool life

According to Taylor's tool life

VT^n=c

where V is cutting velocity

T=tool life of tool

80 % tool life reduction i.e. New tool Life is 0.2T

Thus

VT^{0.12}=V'\left ( 0.2T\right )^{0.12}

V'=\frac{V}{0.2^{0.12}}

V'=\frac{V}{0.824}=1.213V

Thus a change of 21.3 %(increment) is required to reduce tool life by 80%

6 0
3 years ago
Tech A says that some starters use gear reduction to improve efficiency. Tech B says that a starter converts electrical energy t
8_murik_8 [283]

Answer:

Explanation:

B

7 0
3 years ago
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