Answer:
Output of plant=207.18 MW
Explanation:
Given input energy Q=450 MW
Brayton cycle efficiency
%
Rankine cycle efficiency 
%
Combined efficiency for two cycle given as follow
We know that efficiency 
out put of plant=
So output of plant=207.18 MW
Answer:
The right answer is "36.32 W/mk".
Explanation:
According to the question,
TiC = 76%
or,
= 0.76
CO = 24%
or,
= 0.24
Thermal conductivity of TiC,
= 26 W/mk
Thermal conductivity of CO,
= 69 W/mk
On applying the rule, we get
⇒ 
On putting the given values, we get
⇒ 
⇒ 
⇒ 
I believe number 4 I could be wrong but I think it’s 4
Answer:64.10 Btu/lbm
Explanation:
Work done in an isothermally compressed steady flow device is expressed as
Work done = P₁V₁ In { P₁/ P₂}
Work done=RT In { P₁/ P₂}
where P₁=13 psia
P₂= 80 psia
Temperature =°F Temperature is convert to °R
T(°R) = T(°F) + 459.67
T(°R) = 55°F+ 459.67
=514.67T(°R)
According to the properties of molar gas, gas constant and critical properties table, R which s the gas constant of air is given as 0.06855 Btu/lbm
Work = RT In { P₁/ P₂}
0.06855 x 514.67 In { 13/ 80}
=0.06855 x 514.67 In {0.1625}
= 0.06855 x 514.67 x -1.817
=- 64.10Btu/lbm
The required work therefore for this isothermal compression is 64.10 Btu/lbm
