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3 years ago

NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

1 answer:

6 0

A catalyst is a substance that alters the reaction and doesn't involve in the reaction.So if the Manganese was a catalyst the mass would not have decreased,it would just continue aletring the reaction until its used up.
The Manganese is not acting as a catalyst

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What energy transformations occur in a tv remote?

Tatiana [17]

Pressing the button: Mechanical to electrical
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Waste energy from this step: electrical to heat 
Chemical energy from battery: chemical to electrical

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3 years ago

A soccer player kicks a ball from the ground with a speed of 16 m/s at an angle of 63°.

stepladder [879]

A. Horizontal component: 7.3 m/s

Explanation:

The horizontal component of the velocity is given by:

$v_x = v_0 cos \theta$

where

$v_0 = 16 m/s$ is the magnitude of the initial velocity

$\theta=63^{\circ}$ is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

$v_x = (16 m/s) cos 63^{\circ}=7.3 m/s$

B. Vertical component: 14.3 m/s

Explanation:

The vertical component of the velocity is given by:

$v_y = v_0 sin \theta$

where

$v_0 = 16 m/s$ is the magnitude of the initial velocity

$\theta=63^{\circ}$ is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

$v_y = (16 m/s) sin 63^{\circ}=14.3 m/s$

6 0

3 years ago

What will happen when two identical waves that are out of phase with each other combine?

timama [110]

They end up cancelling each other out in a process called destructive interference

6 0

3 years ago

Question 5 of 10

spayn [35]

Answer: A) 0.19 kg.m/s South just answered it right on Apex!

Explanation:

4 0

3 years ago

A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori

marshall27 [118]

Answer:

$K_2=6.4J$

Explanation:

According to the principle of conservation of momentum, we have:

$\Delta p=0\\p_i=p_f\\m_1v_1_i +m_2v_2_i=m_1v_1_f+m_2v_2_f$

Here 1 is for the bullet and 2 is for the block. Since the block is initially at rest $v_i_2=0$ . Solving for $v_2_f$ and replacing the given values:

$v_2_f=\frac{m_1(v_1_i-v_1_f)}{m_2}\\v_2_f=\frac{10*10^{-3}kg(1.8\frac{km}{s}-1\frac{km}{s})}{5kg}\\v_2_f=0.0016\frac{km}{s}*\frac{1000m}{1km}=1.6\frac{m}{s}$

The kinetic energy of the block is given by:

$K_2=\frac{m_2(v_f_2)^2}{2}\\K_2=\frac{5kg(1.6\frac{m}{s})^2}{2}\\K_2=6.4J$

3 0

3 years ago